Laravel 5.2 JSON对使用错误api_令牌的请求的响应
我在controller Laravel 5.2中使用auth:api中间件Laravel 5.2 JSON对使用错误api_令牌的请求的响应,laravel,laravel-5,laravel-5.2,laravel-middleware,Laravel,Laravel 5,Laravel 5.2,Laravel Middleware,我在controller Laravel 5.2中使用auth:api中间件 class RestfulController extends Controller { public function __construct() { $this->middleware(['api', 'auth:api'], ['except' => ['login'] ]); } } 路线: 若请求不包含或包含无效的api
class RestfulController extends Controller
{
public function __construct() {
$this->middleware(['api', 'auth:api'], ['except' => ['login'] ]);
}
}
路线:
若请求不包含或包含无效的api_令牌,框架将重定向到登录页面。相反,我希望返回带有错误的JSON响应。如何实现它?您应该检查api和auth:api中间件组,并查找正在执行此操作的那个。如果它位于供应商包中,则需要对其进行扩展并进行更改。更改app/Http/Middleware/Authenticate.php handle方法,它将响应json
public function handle($request, Closure $next, $guard = null)
{
if (Auth::guard($guard)->guest()) {
if ($request->ajax() || $request->wantsJson()) {
return response('Unauthorized.', 401);
} else {
$response = [
'status' => 'error',
'message' => 'This is error message'
];
return Response::json($response);
}
}
return $next($request);
}
您好,您可以显示您的路由文件吗?请给出一个更好的取消驻留示例
public function handle($request, Closure $next, $guard = null)
{
if (Auth::guard($guard)->guest()) {
if ($request->ajax() || $request->wantsJson()) {
return response('Unauthorized.', 401);
} else {
$response = [
'status' => 'error',
'message' => 'This is error message'
];
return Response::json($response);
}
}
return $next($request);
}