php中字符串到二维数组的转换
我只是想问一下如何在php中将字符串转换成二维数组。请参考下面的示例代码php中字符串到二维数组的转换,php,arrays,Php,Arrays,我只是想问一下如何在php中将字符串转换成二维数组。请参考下面的示例代码 $coordinates = "9.499819 123.920318,9.490845 123.916563,9.484644 123.922292,9.49148 123.931519,9.499755 123.925683,9.499819 123.920318"; 我想把上面的字符串转换成下面的数组,并把它赋给变量 $polygon = array(array('lat' => 9.49
$coordinates = "9.499819 123.920318,9.490845 123.916563,9.484644 123.922292,9.49148 123.931519,9.499755 123.925683,9.499819 123.920318";
我想把上面的字符串转换成下面的数组,并把它赋给变量
$polygon = array(array('lat' => 9.499819,'lng'=>123.920318),
array('lat' => 9.490845,'lng'=>123.916563),
array('lat' => 9.484644,'lng'=>123.922292),
array('lat' => 9.49148,'lng'=>123.931519),
array('lat' => 9.499755,'lng'=>123.925683),
array('lat' => 9.499819,'lng'=>123.920318)
);
对于一个新的贡献者,我认为使用foreach的解决方案更容易理解。 代码中对这些步骤进行了注释
$coordinates = "9.499819 123.920318,9.490845 123.916563,9.484644 123.922292,9.49148 123.931519,9.499755 123.925683,9.499819 123.920318";
$polygon = explode(',',$coordinates);
/*
array (
0 => "9.499819 123.920318",
1 => "9.490845 123.916563",
*/
foreach($polygon as $index => $latLng){
//The element $latLng is split into two variables with list and explode.
list($lat,$lng) = explode(' ',$latLng);
//The elements are replaced by a new array with the variables $lat and $lng as float
$polygon[$index] = ['lat' => (float)$lat, 'lng' => (float)$lng];
}
//test output
echo '<pre>';
var_export($polygon);
看看这个:使用
分解两次,一次使用,
获得对,然后使用(空格)获得单个值。您确实需要向我们展示您自己(代码)解决此问题的最佳尝试,这样我们可以帮助您。请阅读。嗨,伙计们,谢谢你们花时间提出我的问题。嗨,吉布斯特罗斯,下次一定会的。
array (
0 =>
array (
'lat' => 9.499819,
'lng' => 123.920318,
),
1 =>
array (
'lat' => 9.490845,
'lng' => 123.916563,
),
2 =>
array (
'lat' => 9.484644,
'lng' => 123.922292,
),
3 =>
array (
'lat' => 9.49148,
'lng' => 123.931519,
),
4 =>
array (
'lat' => 9.499755,
'lng' => 123.925683,
),
5 =>
array (
'lat' => 9.499819,
'lng' => 123.920318,
),
)