在Php中显示两个表数据

我有以下几张表

作者

id | author_name | author_detail | author_bio 

书籍

id | author_id | book_name | book_detail

我想用以下方式显示数据

Author Name ::
Author Detail ::
books :: 1.book1
         2.book2
         3.book3
         4.book4

我尝试了以下问题，但没有按照我的要求工作

select * from authors left join books  on author.id=books.author_id

我试过group concat，但它给出了带有coma separate的图书名称。所以我想在数组中显示图书的详细信息

 select author.author_name,author.author_detail,author.author_bio,group_concat(books.book_name) eft join books  on author.id=books.author_id

我正在像这样导出输出

Array
(
    [0] => Array
        (
            [id] => 1
            [name] => Norm

            [books] => Array
                (
                  [0] =>Array
                    (
                    [id] => 4
                    [book_name] => great wall
                    [created_at] => 2015-09-11 04:45:07
                    [updated_at] => 2015-09-11 04:45:07
                    )

                    [1] =>Array
                    (
                    [id] => 6
                    [book_name] =>new book
                    [created_at] => 2015-09-11 04:45:07
                    [updated_at] => 2015-09-11 04:45:07
                    )
                )
        )
    [1] => Array
        (
            [id] => 2
            [name] => Norm

            [books] => Array
                (
                  [0] =>Array
                    (
                    [id] => 2
                    [book_name] => amazing star
                    [created_at] => 2015-09-11 04:45:07
                    [updated_at] => 2015-09-11 04:45:07
                    )

                    [1] =>Array
                    (
                    [id] => 3
                    [book_name] =>way of journy
                    [created_at] => 2015-09-11 04:45:07
                    [updated_at] => 2015-09-11 04:45:07
                    )
                )

        )

我也检查了这个问题

有谁能帮我显示上面的数据吗？ 谢谢

试试这个：

SELECT 
A.id
A.author_name, 
A.author_detail,
A.author_bio,
B.book_name,
B.created_at,
B.updated_at
FROM books AS B
LEFT JOIN author AS A
ON (A.id=B.author_id)

您将得到如下结果：

id | author_name | author_detail | author_bio | book_name
1  | ari         | some detail   | some bio   | book_ari_1
1  | ari         | some detail   | some bio   | book_ari_2
1  | ari         | some detail   | some bio   | book_ari_3
2  | tester      | some detail   | some bio   | book_tester_1
etc..

$query = "select whatever whatever...";
$records = $database->Execute($query);
foreach ($records as $fields) {
    if ($fields['id'] != $previous_id) echo "Author ...";
    echo "Book whatever whatever ...";
    $previous_id = $fields['id'];
}

$query = "select id, author_name, whatever from author";
$author_records = $database->Execute($query);
foreach ($author_records as $fields) {
    echo "Author: {$fields['author_name']} whatever <br/>";
    $subquery = "select whatever from books where id = whatever";
    $book_records = $database->Execute($subquery);
    foreach ($book_records as $otherfields) {
        echo "Book whatever whatever";
    }
}

要使数组成为预期结果，需要重新构造数组结果。我将评估您的结果数组是否在

$result

变量中

$new_result = array();
foreach ($result as $key => $value) {
    if (empty($new_result[$value['id']]))
    {
        $new_result[$value['id']] = array(
            'id' => $value['id'],
            'name' => $value['name'],
            'books' => array(
                array(
                    'id' => $value['id'],
                    'book_name' => $value['book_name'],
                    'created_at' => $value['created_at'],
                    'updated_at' => $value['updated_at']
                ),
            )
        )
    }
    else
    {
        $new_result[$value['id']]['id'] = $value['id'];
        $new_result[$value['id']]['name'] = $value['name'];
        $new_result[$value['id']]['books'][] = array(
            'id' => $value['id'],
            'book_name' => $value['book_name'],
            'created_at' => $value['created_at'],
            'updated_at' => $value['updated_at']
        );
    }
}

the result will look like your expected. but the key number will be formated as id.

要将

$new\u result

的键重置为递增数，您只需使用函数获取值

---

您可以使用第一个查询完成此操作…但是您必须在记录循环中检查author_id，并且仅在值更改时显示author详细信息（通过将其与存储在变量中的值进行比较）…否则仅显示book详细信息

因此，您的代码可能（非常粗略）如下所示：

id | author_name | author_detail | author_bio | book_name
1  | ari         | some detail   | some bio   | book_ari_1
1  | ari         | some detail   | some bio   | book_ari_2
1  | ari         | some detail   | some bio   | book_ari_3
2  | tester      | some detail   | some bio   | book_tester_1
etc..

$query = "select whatever whatever...";
$records = $database->Execute($query);
foreach ($records as $fields) {
    if ($fields['id'] != $previous_id) echo "Author ...";
    echo "Book whatever whatever ...";
    $previous_id = $fields['id'];
}

$query = "select id, author_name, whatever from author";
$author_records = $database->Execute($query);
foreach ($author_records as $fields) {
    echo "Author: {$fields['author_name']} whatever <br/>";
    $subquery = "select whatever from books where id = whatever";
    $book_records = $database->Execute($subquery);
    foreach ($book_records as $otherfields) {
        echo "Book whatever whatever";
    }
}

一种更直接（虽然稍长）的方法是使用第二个查询：子查询。它将通过第一个（外部）查询的结果在循环内部进行。因此，您的外部查询将获取作者，在显示作者详细信息后，您将对作者的书籍进行单独的查询……并且在外部循环中有一个循环来显示每本书的详细信息

因此，您的代码（非常粗略）如下所示：

id | author_name | author_detail | author_bio | book_name
1  | ari         | some detail   | some bio   | book_ari_1
1  | ari         | some detail   | some bio   | book_ari_2
1  | ari         | some detail   | some bio   | book_ari_3
2  | tester      | some detail   | some bio   | book_tester_1
etc..

$query = "select whatever whatever...";
$records = $database->Execute($query);
foreach ($records as $fields) {
    if ($fields['id'] != $previous_id) echo "Author ...";
    echo "Book whatever whatever ...";
    $previous_id = $fields['id'];
}

$query = "select id, author_name, whatever from author";
$author_records = $database->Execute($query);
foreach ($author_records as $fields) {
    echo "Author: {$fields['author_name']} whatever <br/>";
    $subquery = "select whatever from books where id = whatever";
    $book_records = $database->Execute($subquery);
    foreach ($book_records as $otherfields) {
        echo "Book whatever whatever";
    }
}

$query=“选择id、作者名称、作者的任何内容”；
$author\u records=$database->Execute（$query）；
foreach（$author\u记录为$fields）{
echo“Author:{$fields['Author_name']}无论什么
”；
$subquery=“从id=which的书籍中选择which”；
$book_records=$database->Execute（$subquery）；
foreach（$book_记录为$otherfields）{
呼应“无论什么书”；
}
}

您可以在php中执行此操作，无需进入查询本身，而是在单独的查询中获取这两个数据，即书籍和作者数据

还记得我假设

$result

为作者数据，

$result2

为书籍数据吗

$item=array();
    while($row=mysql_fetch_array($result))
    {
        $id=$row['id'];        
        $item[$id]['name']=$row['name'];
        $item[$id]['id']=$row['id'];
        $item[$id]['books']=array();
        $temp=array();
        while($row1=mysql_fetch_array($result2))
         {
           if($id==$row1['author_id'])
           {
             $temp['id']=$row1['id'];
             $temp['book_name']=$row1['book_name'];
             $temp['created_at']=$row1['created_at'];
             $temp['updated_at']=$row1['updated_at'];
             array_push($item['id']['books'],$temp);
           }           
         }
    }

---

现在这里id被格式化为作者id。要获得类似的数组键，您可以使用

数组值（$item）

可能重复的@AshwiniAgarwal。它不重复。请阅读我的问题查看问题，它将为您提供解决问题的方法。@AshwiniAgarwal.ok谢谢。但我没有尝试过如何做，因为这将返回单独的数组，如[2]=>array（[id]=>2[name]=>david[books]=>array（[0]=>array（[id]=>2[book\u name]=>book2）））书籍中的id是您的作者id或书籍id？如果是书籍id，您需要先选择书籍id。然后从$value['book\u id'解析到数组。谢谢。你的回答解决了我的问题。非常感谢。像上面这样存储数据是一种好的做法还是group concat好？哪一种更好？如果你用group_concat设置结果，那么当书名有逗号（“，”）时就会出错我不确定书名是否允许逗号。顺便说一句，您可以将分隔符组定义为另一个分隔符。但默认情况下，结果限制为1024。您可以更改默认长度。我不能说当前的算法是否更好。这两种算法都在工作。：）