Php 如何使用来自其他对象的方法/如何传递正确的上下文?
错误: 注意:未定义的属性:Person\u Writer::$name in 如何使用来自其他对象的方法/如何传递正确的上下文?Php 如何使用来自其他对象的方法/如何传递正确的上下文?,php,Php,错误: 注意:未定义的属性:Person\u Writer::$name in 如何使用来自其他对象的方法/如何传递正确的上下文? 我想在$obj中使用函数writeName() 您没有扩展基类,而且您有一个输入错误。您也没有调用writeAge()方法。下面是我的作品: class Person_Writer { function writeName ( ){ echo $this ->name; } function writeAge ( ){
我想在$obj中使用函数writeName() 您没有扩展基类,而且您有一个输入错误。您也没有调用writeAge()方法。下面是我的作品:
class Person_Writer {
function writeName ( ){
echo $this ->name;
}
function writeAge ( ){
echo $this ->age;
}
}
class Person {
function __construct($name,$age) {
$this->writer = new Person_Writer;
$this->name= $name;
$this->age = $age;
}
function __call($name, $arguments) {
$writter = $this->writer;
call_user_func(array($this->writer, 'WriteName'));
// call_user_func(array(new Person_Writer, 'WriteName'));
}
}
$obj = new Person('sasha',28);
$obj->writeName();
class个人\作者{
公共函数writeName(){
echo$this->name;
}
函数writeAge(){
echo$this->age;
}
}
类Person扩展Person\u Writer{
函数构造($name,$age){
$this->writer=newperson\u writer;
$this->name=$name;
$this->age=$age;
}
函数调用($name,$arguments){
$writer=$this->writer;
调用用户函数(数组($this->writer,'WriteName');
//调用_user_func(数组(newperson_Writer,'WriteName'));
}
}
$obj=新人('sasha',28岁);
$obj->writeName();
回声“
”;
$obj->writeAge();
我不太确定您在那里尝试做什么,如果您想调用另一个对象的函数,这将起作用:
class Person_Writer {
public function writeName ( ){
echo $this ->name;
}
function writeAge ( ){
echo $this ->age;
}
}
class Person extends Person_Writer{
function __construct($name,$age) {
$this->writer = new Person_Writer;
$this->name= $name;
$this->age = $age;
}
function __call($name, $arguments) {
$writer = $this->writer;
call_user_func(array($this->writer, 'WriteName'));
// call_user_func(array(new Person_Writer, 'WriteName'));
}
}
$obj = new Person('sasha',28);
$obj->writeName();
echo '<br>';
$obj->writeAge();
您为什么在您的Persone\u Writer对象中使用$this->name?这个对象不知道Person对象的变量,这就是为什么会出现未定义的错误
编辑:另一种解决方案是扩展对象的Hexana解决方案。尝试修复打字错误$writer=$this->writer;好的,从否决票来看,我必须记住,今后不要对拼写错误提供任何帮助。你已经注意到,在一篇评论中,这已经足够好了。当提供一个答案时,询问者除了回答“修复是问题”之外。更新了我的答案,所以希望这适用于希望没有继承的OPI,但感谢您的帮助+1
class Person_Writer {
function writeName ($name){
echo $name;
}
function writeAge ($age){
echo $age;
}
}
class Person{
function __construct($name,$age) {
$this->writer = new Person_Writer;
$this->name= $name;
$this->age = $age;
}
function __call($name, $arguments) {
$writer = $this->writer;
$writer->writeName($this->name);
}
}
$obj = new Person('sasha',28);
$obj->writeName();