PHP MySQL查询未返回结果
我正在做一个学校项目,但我的代码在运行时只返回ann HTTP 500错误。PHP和MySQL已正确安装并正常工作。我已经使用INSERT命令对此进行了测试 我的代码:PHP MySQL查询未返回结果,php,mysql,Php,Mysql,我正在做一个学校项目,但我的代码在运行时只返回ann HTTP 500错误。PHP和MySQL已正确安装并正常工作。我已经使用INSERT命令对此进行了测试 我的代码: <?php // Some inputvalues (those are correct) $user = ""; $pass = ""; $host = ""; $db = ""; $conn = mysqli_connect($host, $user, $pass, $db) or die("Het is
<?php
// Some inputvalues (those are correct)
$user = "";
$pass = "";
$host = "";
$db = "";
$conn = mysqli_connect($host, $user, $pass, $db)
or die("Het is niet gelukt om te verbinden met de database!");
// Vaststellen wat je wil weten
$grab = $_GET['grab'];
$query = "SELECT * FROM informaticaproject WHERE id=1";
$result = mysqli_query($conn, $query)
or die("Geen gegevens opgehaald!");
echo $result;
while ($row = mysqli_fetch_assoc($result)) {
$anwer = $row["'" . $grab . "'"];
}
echo $answer;
mysqli_close($conn);
//试试这个
$anwer=$row[$grab]代码>试试这个。应该有用。这不是编码问题,echo$answer代码>分配给应答
并检查应答
。学会有耐心。@RahulMeshram谢谢你,但这不管用。问题是我没有得到任何结果。请先调试!一行一行地走<代码>打印($result)
或尝试插入echo 1代码>介于两者之间。启用。从你自己开始。你能做到。
//Try This
<?php
// Some inputvalues (those are correct)
$user = "";
$pass = "";
$host = "";
$db = "";
$conn = mysqli_connect($host, $user, $pass, $db)
or die("Het is niet gelukt om te verbinden met de database!");
// Vaststellen wat je wil weten
$grab = $_GET['grab'];
$query = "SELECT * FROM informaticaproject WHERE id=1";
$result = mysqli_query($conn, $query)
or die("Geen gegevens opgehaald!");
echo $result;
while ($row = mysqli_fetch_assoc($result)) {
$anwer = $row["'" . $grab . "'"];
}
echo $anwer;
mysqli_close($conn);