Php mysql中计算列和时出错

表tblstationerystock中有一列名为stationeryqtyrecd。我想打印特定数量（如笔）的stationeryqtyrecd的总值。但我的查询显示错误。我的查询为

  <?php
include('includes/config.php');

$sql = "
SELECT SUM(stationeryqtyrecd) as total 
  from tblstationerystock 
 where stationerytype = :type
"; 
$query = $dbh -> prepare($sql);
$query->bindParam(':type', "pen", PDO::PARAM_STR);
$query->execute();
$results=$query->fetchAll(PDO::FETCH_OBJ);
$total=$results->total();



echo $total;

?>

试试这个：

include('includes/config.php');

$type='pen';
$sql = "SELECT SUM(stationeryqtyrecd) as total from tblstationerystock where stationerytype = :type"; 
$query = $dbh -> prepare($sql);
$query->bindParam(':type', $type);
$query->execute();
if($row = $query->fetch(PDO::FETCH_OBJ)) {
    print($row->total);
}

---

您绑定的参数isread不在query@juergend我在代码中更正了它仍然不工作什么错误？请看@jameson2012你能解释或写完整的代码吗？我从total中删除了括号，现在它有错误通知：试图在第10行的C:\xampp\htdocs\sms\admin\test.php中获取非object的属性“total”，我已经测试了这段代码，它工作正常。如果您没有显示任何数据和php错误，那么您的sql查询很可能有问题。我建议您进行一些调试，并检查所有的列名

include('includes/config.php');

$type='pen';
$sql = "SELECT SUM(stationeryqtyrecd) as total from tblstationerystock where stationerytype = :type"; 
$query = $dbh -> prepare($sql);
$query->bindParam(':type', $type);
$query->execute();
if($row = $query->fetch(PDO::FETCH_OBJ)) {
    print($row->total);
}