PHP-基于键映射两个数组
用户阵列PHP-基于键映射两个数组,php,arrays,explode,array-merge,Php,Arrays,Explode,Array Merge,用户阵列 print_R($user_array); Array ( [0] => Array ( [SKILL_NAME] => Application Software [EXPERIENCE_BAND] => 15+ [SITE_STATUS] => Onsite [NO_OF_RESOURCE] => 1 [ACTU
print_R($user_array);
Array
(
[0] => Array
(
[SKILL_NAME] => Application Software
[EXPERIENCE_BAND] => 15+
[SITE_STATUS] => Onsite
[NO_OF_RESOURCE] => 1
[ACTUAL_HOURS] => 16
)
[1] => Array
(
[SKILL_NAME] => Application Software
[EXPERIENCE_BAND] => 2-4
[SITE_STATUS] => Onsite
[NO_OF_RESOURCE] => 1
[ACTUAL_HOURS] => 96
)
)
print_R($value_array);
Array
(
[RATE_PER_HOUR] => 80,50
[MARKUP_PERCENT] => 5,10
[TOTAL_COST] => 8064.00,880.00
)
值数组
print_R($user_array);
Array
(
[0] => Array
(
[SKILL_NAME] => Application Software
[EXPERIENCE_BAND] => 15+
[SITE_STATUS] => Onsite
[NO_OF_RESOURCE] => 1
[ACTUAL_HOURS] => 16
)
[1] => Array
(
[SKILL_NAME] => Application Software
[EXPERIENCE_BAND] => 2-4
[SITE_STATUS] => Onsite
[NO_OF_RESOURCE] => 1
[ACTUAL_HOURS] => 96
)
)
print_R($value_array);
Array
(
[RATE_PER_HOUR] => 80,50
[MARKUP_PERCENT] => 5,10
[TOTAL_COST] => 8064.00,880.00
)
分解值数组<代码>每小时速率<代码>
$rate_per_hour=爆炸(',',$array_data['rate_per_hour'])代码>
下面的输出。MARKUP\u PERCENT
和TOTAL\u COST
Array
(
[0] => 80
[1] => 50
)
如何映射以上两个数组,使输出如下所示。数组映射是基于密钥完成的,以维护正确的数据
Array
(
[0] => Array
(
[SKILL_NAME] => Application Software
[EXPERIENCE_BAND] => 15+
[SITE_STATUS] => Onsite
[NO_OF_RESOURCE] => 1
[ACTUAL_HOURS] => 16
[RATE_PER_HOUR] => 80
[MARKUP_PERCENT] => 5
[TOTAL_COST] => 8064.00
)
[1] => Array
(
[SKILL_NAME] => Application Software
[EXPERIENCE_BAND] => 2-4
[SITE_STATUS] => Onsite
[NO_OF_RESOURCE] => 1
[ACTUAL_HOURS] => 96
[RATE_PER_HOUR] => 50
[MARKUP_PERCENT] => 10
[TOTAL_COST] => 880.00
)
)
分解值数组中的每个值。循环执行此操作,并将它们添加到用户数组的相应元素中
foreach ($value_array as $key => $data) {
$data_array = explode(',', $data);
foreach ($data_array as $index => $val) {
$user_array[$index][$key] = $val;
}
}
您尝试过什么吗?尝试过使用array\u merge,但不确定如何基于密钥执行。您能向我们展示您的代码上下文吗?像
每个人都会尝试数组_merge
,好像这是一个神奇的函数,可以找出程序员想要实现的关系。可能的重复?感谢您的响应。我已经分解了需要添加到mainuser\u array
中的特定键的数组。我不知道如何确切地使用上面的代码段来生成预期的输出。考虑到上面的数组,我应该怎么做呢?只需将$value\u数组的$value
和$user
更改为$user\u数组
,语义。@slimshaddyyy我已经确定了使用数组名称的答案。在更新的代码中,您在哪里设置$data\u数组
?