Php 为什么Mockry返回demeter_getMyClass而不是MyClass？

我尝试模拟多个方法调用。如上所述，要测试以下方法调用：

$object->foo()->bar()->zebra()->alpha()->selfDestruct();

我们可以使用以下代码：

$mock = \Mockery::mock('CaptainsConsole');
$mock->shouldReceive('foo->bar->zebra->alpha->selfDestruct')->andReturn('Ten!');

因此，我实施了它：

public function testProcessPayment()
{
    $offerPayment =  m::mock('MyApp\Model\Entity\OfferPayment');

    $paymentTransaction = m::mock('MyApp\Model\Entity\PaymentTransaction');
    $paymentTransaction->shouldReceive('getOfferPayment->getOffer')->andReturn($offerPayment);

    $transactionManager = new TransactionManager();
    $transactionManager->processPayment($paymentTransaction);

    $this->assertInstanceOf('Offer', $paymentTransaction->getOfferPayment()->getOffer());
}

相关类别：

class TransactionManager
{
    public function processPayment(PaymentTransaction $paymentTransaction) {
        $itemGroupEntity = $paymentTransaction->getOfferPayment()->getOffer();
    }
}

我得到：

Mockry\u 3\u MyApp\u Model\u Entity\u PaymentTransaction:：getOfferPayment（）的返回值必须是MyApp\Model\Entity\OfferPayment、Mockry\u 4\u demeter\u getOfferPayment的实例返回的

---

getOfferPayment和getOffer的实现：

public function getOfferPayment() : OfferPayment
{
    return $this->offerPayment;
}


public function getOffer() : Offer
{
    return $this->offer;
}

---

在这种情况下，嘲弄不支持。 可以通过删除getter的返回类型声明来解决此问题：

public function getOfferPayment()
{
    return $this->offerPayment;
}


public function getOffer()
{
    return $this->offer;
}