Php 如何将所有日期提取到select数据表中

我将所有日期提取到my report表中。但它仅包含time\u in和time\u out记录的日期。我希望将所有日期提取到表中，time\u in和time\u out以及total hours列为空。如何解决此问题

$query = "
    SELECT * FROM month_data
    INNER JOIN nonacadamic
    ON month_data.Emp_no = nonacadamic.emp_id 
    WHERE nonacadamic.emp_id = '".$_POST["emp_id"]."'";
    $statement = $connect->prepare($query);
    if($statement->execute())
    {   
        $result = $statement->fetchAll();
        $output = '<div class="row container">';

        $table='<table class="table table-bordered table-hover" id="table">';
        $table.='<tr><th>Date</th><th>Time In</th><th>Time Out</th><th>Total Hrs.</th></tr>';
        $emp_id = '';
        $emp_name = '';
        $Section = '';
        $Designation = '';
        $strat = date('Y-M-01');
        $end = date('Y-M-d');
        // Specify the start date. This date can be any English textual format  
        $date_from = $strat;   
        $date_from = strtotime($date_from); // Convert date to a UNIX timestamp  

        // Specify the end date. This date can be any English textual format  
        $date_to = $end;  
        $date_to = strtotime($date_to); // Convert date to a UNIX timestamp  

       // Loop from the start date to end date and output all dates inbetween  
        for ($i=$date_from; $i<=$date_to; $i+=86400) {  
              echo date("Y-m-d D", $i).'<br />';  
        }  
        foreach($result as $row)
        {
            $date = date_format( date_create($row['Date']), 'Y-m-d D' ) ; 


        if($emp_id != sprintf('%05d',$row["emp_id"]) && $emp_name != $row['emp_name'] && $Section != ucwords($row['Section']) && $Designation !=ucwords($row['Designation']) ) {

        $output.='<div class="col-sm-4"><b>Name   :</b><span> &nbsp;'. $row["emp_name"] .'</span></div>
                  <div class="col-sm-4">&nbsp;</div>
                  <div class="col-sm-4"><b>Emp. No    :</b><span> &nbsp;'. sprintf('%05d',$row["emp_id"]) .'</span></div>' ;
        $output .= '<div class="col-sm-12">&nbsp;</div>';
        $output.='<div class="col-sm-4"><b>Division    :</b><span> &nbsp;'. ucwords($row['Section']).'</span></div>
                  <div class="col-sm-4"><b>Designation    :</b> <span> &nbsp;'. ucwords($row['Designation']).'</span></div>
                  <div class="col-sm-4"><b>Period    :</b><span> &nbsp;'.$strat.' - '.$end.'</span></div>' ;
        $output .= '<div class="col-sm-12">&nbsp;</div>';

         }
        $emp_id= sprintf('%05d',$row["emp_id"]);
        $emp_name = $row['emp_name'];
        $Section = ucwords($row['Section']);
        $Designation = ucwords($row['Designation']);

         $table .='<tr class="info">';
         $table .='<td border border-dark>' . date_format( date_create($row['Date']), 'Y-m-d D' ) . '</td>';
         $table .='<td border border-dark>' . $row['Time_in'] . '</td>'; 
         $table .='<td border border-dark>' . $row['Time_out'] . '</td>';
         $table .='<td border border-dark>' . $row['Total_hours'] . '</td>';
         $table .='</tr>';
         }
          $table .='</table>';
          $output .= '</div>';
        echo $output.$table;

    }

我还得到了当前月份的所有日期。但是我可以附加到当前表中的日期。我非常感谢您的帮助

我想把设置好的剩余日期提取到表中。

---

考虑以下几点：

<?php

$array = array(1,2,3,5,7,11);

for($i=1;$i<=12;$i++){
  if(in_array($i,$array)){echo $i.' yes<br>';} else {echo $i.' no<br>';}
    }


?>

---

这可能对我有帮助。我会试试。谢谢你的关注

1 yes
2 yes
3 yes
4 no
5 yes
6 no
7 yes
8 no
9 no
10 no
11 yes
12 no