如何在不重复重复数据的情况下正确设置PHP while循环

我看过无数以前的问题，找不到一个与我现在的问题相同的问题。我有一个工作脚本，可以从数据库中获取所需的数据

<?php
$result = $conn->query("SELECT COUNT(colUser) AS userCount, colMonth as userMonth, colYear as userYear FROM MyTable GROUP BY userYear");
$newData = array();
$years = array();
$cnt = array();
while($selected_row = $result->fetch(PDO::FETCH_ASSOC)) {
    array_push($years,$selected_row['userMonth']);
    $tmp_key = $selected_row['userYear'];

    array_push($cnt,$selected_row['userCount']);
    $newData[$tmp_key] = array(
       implode(',',$cnt)
    );
}
$jsonResult = json_encode($newData);


echo $jsonResult;

我得到的结果是

{
  "2018": ["292,181,1868,1074,2726,2213,2616,3269,1744,2839,1983,1689"],
  "2019": ["292,181,1868,1074,2726,2213,2616,3269,1744,2839,1983,1689,2179,2027,1948,2071,2323,1963,2721,4065,4626,4660,3783,3170"],
  "2020": ["292,181,1868,1074,2726,2213,2616,3269,1744,2839,1983,1689,2179,2027,1948,2071,2323,1963,2721,4065,4626,4660,3783,3170,4308,3307,6143,6795,1881"]
}

此外，如果可能的话，更理想的产出是（用零填充空月份）

---

我真诚地感谢你的帮助

在格鲁比克劳顿公司的指导下，我成功地实现了我想要的结果

$result = $conn->query("SELECT COUNT(colUser) AS userCount, colMonth as userMonth, colYear as userYear FROM MyTable GROUP BY userYear");
$newData = array();
$years = array();
$cnt = array();
while($selected_row = $result->fetch(PDO::FETCH_ASSOC)) {
    array_push($years,$selected_row['userMonth']);
    $tmp_key = $selected_row['userYear'];
    $newData[$tmp_key][] = $selected_row['userCount'];
}
$jsonResult = json_encode($newData);


echo $jsonResult;

---

为什么要将值作为单个字符串存储在数组中？换句话说，您可以只做

$newData[$tmp_key]=$cnt

，而不是

内爆（'，'$cnt）

——如果您不想重复值，则需要保留已使用值的列表，并确保不再添加这些值。如果我们能在while循环之前看到您的数据是如何格式化的，这对我们也会有很大帮助。我不会说我是数组新手，但还不是完全的中级。因此，如果我做了一些不正确的事情，我是不知道的。while循环之前的数据只是从SQL查询返回的数据。没什么特别的。数据库只有年和月列，然后是用户ID。我知道我可以通过第二次查询来完成我想要的，但我试图避免这样做。

{
  "2018": ["292,181,1868,1074,2726,2213,2616,3269,1744,2839,1983,1689"],
  "2019": ["2179,2027,1948,2071,2323,1963,2721,4065,4626,4660,3783,3170"],
  "2020": ["4308,3307,6143,6795,1881,0,0,0,0,0,0,0"]
}

$result = $conn->query("SELECT COUNT(colUser) AS userCount, colMonth as userMonth, colYear as userYear FROM MyTable GROUP BY userYear");
$newData = array();
$years = array();
$cnt = array();
while($selected_row = $result->fetch(PDO::FETCH_ASSOC)) {
    array_push($years,$selected_row['userMonth']);
    $tmp_key = $selected_row['userYear'];
    $newData[$tmp_key][] = $selected_row['userCount'];
}
$jsonResult = json_encode($newData);


echo $jsonResult;