解析sql查询PHP
我想将SQL查询解析为数组。我搞不懂密码 例如:解析sql查询PHP,php,sql,parsing,Php,Sql,Parsing,我想将SQL查询解析为数组。我搞不懂密码 例如: $sql_query = "SELECT id, login, pass FROM users WHERE id=3, login=faforty ORDER DESC LIMIT 3"'; 此sql查询应如下所示: $data = array(); $data['select'] = array('id', 'login', 'pass'); $data['from'] = array('id' => 3, 'login' =>
$sql_query = "SELECT id, login, pass FROM users WHERE id=3, login=faforty ORDER DESC LIMIT 3"';
此sql查询应如下所示:
$data = array();
$data['select'] = array('id', 'login', 'pass');
$data['from'] = array('id' => 3, 'login' => 'faforty');
$data['order'] = 'desc';
$data['limit'] = 3;
查询可能不同。使用SQL解析器
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如何获取数组到SQL查询?您应该作为一个新问题提问,因为它与此问题/答案无关。哦,是的!我是按照你对上述问题的建议来做的。现在我希望输出数组应该是查询againHi!这些天我正在为PHP7.4 | 8.x设计一个新版本的SQL解析器。我将发布一个更新与每一个稳定的变化。
<?php
require_once('php-sql-parser.php');
$parser=new PHPSQLParser('SELECT a FROM some_table an_alias WHERE d > 5;', true);
print_r($parser->parsed);
Array
(
[SELECT] => Array
(
[0] => Array
(
[expr_type] => colref
[alias] =>
[base_expr] => a
[sub_tree] =>
[position] => 8
)
)
[FROM] => Array
(
[0] => Array
(
[expr_type] => table
[table] => some_table
[alias] => Array
(
[as] =>
[name] => an_alias
[base_expr] => an_alias
[position] => 29
)
[join_type] => JOIN
[ref_type] =>
[ref_clause] =>
[base_expr] => some_table an_alias
[sub_tree] =>
[position] => 18
)
)
[WHERE] => Array
(
[0] => Array
(
[expr_type] => colref
[base_expr] => d
[sub_tree] =>
[position] => 45
)
[1] => Array
(
[expr_type] => operator
[base_expr] => >
[sub_tree] =>
[position] => 47
)
[2] => Array
(
[expr_type] => const
[base_expr] => 5
[sub_tree] =>
[position] => 49
)
)
)