Php 尝试在字段下方显示消息时出错
如果我的联系人表单的必填字段为空,我想在该字段下方显示一条错误消息。我跟踪了这个链接Php 尝试在字段下方显示消息时出错,php,html,Php,Html,如果我的联系人表单的必填字段为空,我想在该字段下方显示一条错误消息。我跟踪了这个链接 http://stackoverflow.com/questions/11237655/display-form-validation-errors-next-to-each-field 我的代码如下: send.php $error = array( "name" => "", "email" => "", "message" => ""
http://stackoverflow.com/questions/11237655/display-form-validation-errors-next-to-each-field
我的代码如下:
send.php
$error = array(
"name" => "",
"email" => "",
"message" => ""
);
if(empty()$_POST["email"])
$error["email"] = "Email is required!";
if(empty()$_POST["name"])
$error["name"] = "Name is required!";
if(empty()$_POST["message"])
$error["message"] = "Message is required!";
但我得到的错误如下:
Parse error: syntax error, unexpected ')', expecting T_STRING or T_VARIABLE or '$' in send.php on line 20
第20行是if(empty()$\u POST[“email”])
我的代码中有什么错误?修复检查。也许最好加上
从
到
在将字符串传递到
empty
之前,请尝试此代码,不要忘记执行trim
,同时使用isset
<?php
$error = array(
"name" => "",
"email" => "",
"message" => ""
);
$email = ( isset( $_POST["email"] ) ) ? trim( $_POST["email"] ) : false;
$name = ( isset( $_POST["name"] ) ) ? trim( $_POST["name"] ) : false;
$message = ( isset( $_POST["message"] ) ) ? trim( $_POST["message"] ) : false;
if ( !$emai ) {
$error["email"] = "Email is required!";
}
if ( !$name ) {
$error["name"] = "Name is required!";
}
if ( !$message ) {
$error["message"] = "Message is required!";
}
?>
if(空($\u POST[“email”])
其他问题同上,我按照您的说明更正了,我甚至按照上面链接中的教程以html格式进行了编辑。但是我没有收到消息你说没有收到消息是什么意思?你是在给自己发送邮件吗?你是如何输出消息的?isset
如果发送了一个post字段email
,即使它是空的,没有值,也会返回true谢谢,但即使我添加了,我也不会收到错误消息为什么使用empty
?由于上面已经设置了一个值,如果($email){//has email value}也这样做,则不会显示该值吗?@PuneethP设置错误时不会显示该值。之后必须打印错误。添加print\r($error)
并查看它是否在there@PuneethP,正如他所说,要显示错误消息,您需要使用echo
或print\r
@bystwn22。我想您的意思是,如果(!$email)感叹号丢失,则将其更新为
if(!isset($_POST["email"]) || empty($_POST["email"]))
<?php
$error = array(
"name" => "",
"email" => "",
"message" => ""
);
$email = ( isset( $_POST["email"] ) ) ? trim( $_POST["email"] ) : false;
$name = ( isset( $_POST["name"] ) ) ? trim( $_POST["name"] ) : false;
$message = ( isset( $_POST["message"] ) ) ? trim( $_POST["message"] ) : false;
if ( !$emai ) {
$error["email"] = "Email is required!";
}
if ( !$name ) {
$error["name"] = "Name is required!";
}
if ( !$message ) {
$error["message"] = "Message is required!";
}
?>