Php 将结果发布回搜索表单所在的页面

我正在做一个项目，需要一些帮助，请：）（完整的代码在底部）

项目需要通过PDO访问。
我需要搜索结果显示在搜索输入的同一页上

在我看来，用GET代替POST似乎不太合适。。这是正确的吗？ 这是可行的，但我需要删除/隐藏第一次加载页面（index.php）时出现的这段代码

if(!isset($_GET['search']))
{   echo "Error, Please go back.";  exit;}

我该怎么做

另外，我的第二个问题是，我无法让搜索表单在表中搜索多个字段。它只是不让我。我也不能使用这段代码

%'.$searchterm.'%

因为它不会给我任何搜索反馈。所以我用的是

:searchterm

在

这是我的全部代码：

<?php

$servername = 'localhost';
$username = "root";
$password = "";
$dbname = "u1360138";

<?php
if(isset($_POST['search'])){
    echo 'Search';
}
?>


<!-- Search facility 1 -->
<form action="index.php" method="get">
<label for="search">Enter a weight class. Need to be more than one searchs which wont work</label>
<input type="text" name="search" id="search">
<input type="submit" value="Search">
</form>
<?php
// DB Connection
try {$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);}
catch(PDOException $e)
{echo "Error conntecting to the DB: " . $e->getMessage();}
if(!isset($_GET['search']))
{   echo "Error, Please go back.";  exit;}
// DB Connection


$searchterm = $_GET['search'];
$stmt = $conn->prepare("SELECT * FROM boxer WHERE weightclass LIKE :searchterm");
$stmt->bindValue(':searchterm','%'.$searchterm.'%');
$stmt->execute();
// loop displays loop
while ($boxer = $stmt->fetch(PDO::FETCH_OBJ))
{ echo "<ul>";
echo "<a href='details.php?idboxer=".$boxer->idboxer."'>";
echo "<li>".$boxer->firstname." ".$boxer->lastname."</li>";
echo "</a>";
echo "</ul>"; }
$conn=NULL;
?>

输入一个权重类。需要一个以上的搜索，这是行不通的

在良好实践中，当用户向服务器发送将更改服务器上数据的内容时，使用POST发送参数（例如存储在数据库中或发送电子邮件）。当用户从服务器检索数据时，使用GET来读取数据（查询数据库）。所以我宁愿到这里

为了解决您的问题，只需将处理研究的整个代码放在“if（isset（$\u GET['search']）{}”部分，如下所示：

<?php

$servername = 'localhost';
$username = "root";
$password = "";
$dbname = "u1360138";

<?php
if(isset($_GET['search'])){
    echo 'Search';
}
?>


<!-- Search facility 1 -->
<form action="index.php" method="get">
<label for="search">Enter a weight class. Need to be more than one searchs which wont work</label>
<input type="text" name="search" id="search">
<input type="submit" value="Search">
</form>
<?php

if(isset($_GET['search'])){
  // DB Connection
  try {$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);}
  catch(PDOException $e)
  {echo "Error conntecting to the DB: " . $e->getMessage();}
  // DB Connection


  $searchterm = $_GET['search'];
  $stmt = $conn->prepare("SELECT * FROM boxer WHERE weightclass LIKE :searchterm");
  $stmt->bindValue(':searchterm','%'.$searchterm.'%');
  $stmt->execute();
  // loop displays loop
  while ($boxer = $stmt->fetch(PDO::FETCH_OBJ))
  { 
    echo "<ul>";
    echo "<a href='details.php?idboxer=".$boxer->idboxer."'>";
    echo "<li>".$boxer->firstname." ".$boxer->lastname."</li>";
    echo "</a>";
    echo "</ul>"; 
   }
   $conn=NULL;
 }
?>

输入一个权重类。需要一个以上的搜索，这是行不通的

我觉得用GET代替POST似乎不合适。。这是正确的吗？这是可行的，但我需要删除/隐藏第一次加载页面（index.php）时出现的这段代码。

这取决于您希望何时使用

GET

或

POST

。POST更安全，所以对于提交表单，我总是使用

POST

。在这种情况下，您可以保留以下代码：

if(isset($_POST['search'])){
    echo 'Search';
}

您确实需要将表单的

操作

类型更改为

POST

：

<form action="index.php" method="post">
....

---

所以我想出来了

<!-- HTML FORM SEARCH BAR -->
<form action="index.php" method="post">
<label for="enteredterm">Enter a Weight-class or a Nationality:</label>
<input type="text" name="enteredterm">
<input type="submit" name="search">
</form>
<!-- HTML FORM SEARCH BAR -->

if(isset($_POST['search'])){
$enteredterm = $_POST['enteredterm'];

if ($enteredterm ===""){
echo "error, enter something.";
} else {

$stmt = $conn->prepare("SELECT * FROM boxer WHERE weightclass LIKE     :enteredterm OR nationality LIKE :enteredterm or lastname LIKE :enteredterm     ORDER BY year");
$stmt->bindValue(':enteredterm','%'.$enteredterm.'%');
$stmt->execute();
$count= $stmt->rowCount();

echo "You entered ".$enteredterm." and returned ";
if($count <= 1){
echo $count." result.";
}else{
echo $count." results.";
}
// loop displays loop
while ($boxer = $stmt->fetch(PDO::FETCH_OBJ))
{ echo "<ul>";
echo "<a href='details.php?idboxer=".$boxer->idboxer."'>";
echo "<li>".$boxer->firstname." ".$boxer->lastname."</li>";
echo "</a>";
echo "</ul>"; }

输入体重等级或国籍：
如果（isset（$_POST['search']））{
$enteredterm=$\u POST['enteredterm']；
如果（$enteredterm==“”）{
echo“错误，请输入内容。”；
}否则{
$stmt=$conn->prepare（“从boxer中选择*，其中weightclass如：enteredterm或national如：enteredterm或lastname如：enteredterm ORDER BY year”）；
$stmt->bindValue（':enteredterm'，'%.$enteredterm'%'）；
$stmt->execute（）；
$count=$stmt->rowCount（）；
echo“您输入了”.$enteredterm.“并返回”；
if（$count fetch（PDO:：fetch_OBJ））
{echo“
”；
回声“；
回声“
”；}

LIKE%:searchterm%

并从BindValueDrop%这将永远不会发生

“”；

不完整。为什么不使用ajax将表单数据处理到服务器，并获取响应以在同一页面上再次显示它？如果将表单设置为post，则If应该可以正常工作。另外，与搜索相关的其余代码也应该封装在If中。

$searchterm = $_POST['search'];

<!-- HTML FORM SEARCH BAR -->
<form action="index.php" method="post">
<label for="enteredterm">Enter a Weight-class or a Nationality:</label>
<input type="text" name="enteredterm">
<input type="submit" name="search">
</form>
<!-- HTML FORM SEARCH BAR -->

if(isset($_POST['search'])){
$enteredterm = $_POST['enteredterm'];

if ($enteredterm ===""){
echo "error, enter something.";
} else {

$stmt = $conn->prepare("SELECT * FROM boxer WHERE weightclass LIKE     :enteredterm OR nationality LIKE :enteredterm or lastname LIKE :enteredterm     ORDER BY year");
$stmt->bindValue(':enteredterm','%'.$enteredterm.'%');
$stmt->execute();
$count= $stmt->rowCount();

echo "You entered ".$enteredterm." and returned ";
if($count <= 1){
echo $count." result.";
}else{
echo $count." results.";
}
// loop displays loop
while ($boxer = $stmt->fetch(PDO::FETCH_OBJ))
{ echo "<ul>";
echo "<a href='details.php?idboxer=".$boxer->idboxer."'>";
echo "<li>".$boxer->firstname." ".$boxer->lastname."</li>";
echo "</a>";
echo "</ul>"; }