在PHP中创建多维数组
我有一个数据库查询结果,它是一个数组,如下所示:在PHP中创建多维数组,php,multidimensional-array,Php,Multidimensional Array,我有一个数据库查询结果,它是一个数组,如下所示: [{"uid":29,"totalAmount":"5400.00"}, {"uid":499,"totalAmount":"5400.00"}, {"uid":507,"totalAmount":"3960.00"}, {"uid":497,"totalAmount":"3960.00"}, {"uid":498,"totalAmount":"3960.00"}, {"uid":34,"totalAmount":"3960.00"},
[{"uid":29,"totalAmount":"5400.00"},
{"uid":499,"totalAmount":"5400.00"},
{"uid":507,"totalAmount":"3960.00"},
{"uid":497,"totalAmount":"3960.00"},
{"uid":498,"totalAmount":"3960.00"},
{"uid":34,"totalAmount":"3960.00"},
{"uid":21,"totalAmount":"3240.00"},
{"uid":27,"totalAmount":"2880.00"},
{"uid":500,"totalAmount":"2880.00"},
{"uid":19,"totalAmount":"2700.00"},
{"uid":22,"totalAmount":"2700.00"},
{"uid":20,"totalAmount":"2520.00"},
{"uid":23,"totalAmount":"2520.00"},
{"uid":504,"totalAmount":"1800.00"},
{"uid":496,"totalAmount":"1440.00"},
{"uid":26,"totalAmount":"1260.00"},
{"uid":491,"totalAmount":"1080.00"},
{"uid":492,"totalAmount":"720.00"},
{"uid":464,"totalAmount":"540.00"},
{"uid":493,"totalAmount":"540.00"},
{"uid":76,"totalAmount":"540.00"},
{"uid":505,"totalAmount":"180.00"},
{"uid":506,"totalAmount":"180.00"},
{"uid":494,"totalAmount":"180.00"},
{"uid":495,"totalAmount":"180.00"}]
根据这个结果,我想创建一个多维数组,如下所示:
[
"0" =>
[
"0"=>["uid"=>29, "totalAmount"=>5400 ],
"1"=>["uid"=>499, "totalAmount"=>5400]
],
"1" =>
[
"0"=>["uid"=>507, "totalAmount"=>3960 ],
"1"=>["uid"=>497, "totalAmount"=>3960],
"2"=>["uid"=>498, "totalAmount"=>3960 ],
"3"=>["uid"=>34, "totalAmount"=>3960],
],
]
// and so on ...
我已尝试使用foreach
:
$topEar = [];
$amount = '';
foreach( $topEarners as $te)
{
array_push($topEar, [$te->uid=>$te->totalAmount]);
}
$topEar;
您可以这样做:
$topEar = array();
$currAmountArray = array();
$amount = null;
foreach( $topEarners as $te) {
if( !is_null($amount) && $te->totalAmount != $amount ) {
array_push($topEar, $currAmountArray);
$currAmountArray = array();
}
array_push($currAmountArray, $te);
$amount = $te->totalAmount;
}
if( !empty($currAmountArray) ) {
array_push($topEar, $currAmountArray);
}
print_r($topEar);
您在每次迭代中保存最后一个$totalAmount
,只要它不改变-您将值存储在名为$currAmountArray
的子数组中,当$totalAmount
改变时,您将值推送到主数组
我还在
foreach
循环之后添加了一个条件,以确保$currAmountArray
中的最后一部分数据也将被推入主数组(即$topEar
)。如果无法使用SQL获得所需的结构,那么这将是PHP中最简单的方法:
$topEarners = json_decode($json, true);
foreach($topEarners as $row) {
$result[$row['totalAmount']][] = $row;
}
- 将JSON解码为PHP数组
- 使用
作为键循环并附加到数组中totalAmount
$result = array_values($result);
实际输出与预期输出有何不同?第一个字符串类似于json。您是否尝试过json_decode()?我也不明白你是怎么从第一个字符串到第二个字符串的。请澄清这一点。我认为这个问题不值得投否决票。因此,您需要根据
totalAmount
对值进行分组?为什么不将分组依据添加到query@AlonEitan在提取数据及其对象数组时,它已经使用用户id进行分组。您有多个具有相同用户id的行?为什么OP“要这样做”?一个好的答案总是会有一个解释,说明做了什么以及为什么这样做,不仅是为了OP,也是为了SO的未来访问者。@JayBlanchard正确,我现在正在编辑它,并给出一些适当的解释