Php 接收未定义的偏移量1

当用户使用facebook登录时，我尝试从facebook获取他们的图片并将其上传到我自己的网站服务器，但我收到错误未定义偏移量1，我不知道为什么会出现此错误代码如下

$url = "https://graph.facebook.com/$fbid/picture?width=410&height=310"; //$fbid is the fbid of user //
$no = imd(); //  imd); is a function that generat random string //
$name = basename($url);
list($txt, $ext) = explode(".", $name);
$name = $txt.time();
$jo = ".jpg";
$name = $no.$jo;

$upload = file_put_contents("profile/upload/$name",file_get_contents($url));

$pic = $name;

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正如我在上面的评论中所说，错误来自

list（$txt，$ext）=explode（“.”，$name）因为分解的结果是一个只有一个元素的数组
array（1）{[0]=>string（28）“picture？width=410&height=310”}

您可以将代码简化为：

$url = "https://graph.facebook.com/$fbid/picture?width=410&height=310"; //$fbid is the fbid of user //
$no = imd(); //  imd); is a function that generat random string //
// $name = basename($url); // COMMENT THIS  since you have another assignment for this variable below
// list($txt, $ext) = explode(".", $name); // you didn't use $ext, and since we commented out the next line, $txt won't be used
// $name = $txt.time(); // COMMENT THIS  since you have another assignment for this variable below
$jo = ".jpg";
$name = $no.$jo;

$upload = file_put_contents("profile/upload/$name",file_get_contents($url));

$pic = $name;

您的$url出现错误。我认为您发送了错误的参数。错误来自
list（$txt，$ext）=explode（“.”，$name）
因为explode的结果是一个只有一个元素的数组
数组（1）{[0]=>字符串（28）“picture？width=410&height=310”}
@Monty这个参数完全正确，就像有人访问facebook时重定向到@PrinceG如何纠正这个错误？@PrinceG那么如何获得图像的名称，我很困惑