Php 复制图像文件
我正在上传一个图像文件,复制它,调整它的大小,然后移动原始文件并调整它的大小 我已经编写了以下函数,我知道有很多空间来整理代码等等Php 复制图像文件,php,Php,我正在上传一个图像文件,复制它,调整它的大小,然后移动原始文件并调整它的大小 我已经编写了以下函数,我知道有很多空间来整理代码等等 public function useImage($image, $photoid){ $source = $image['tmp_name']; $target = "projectimages/"; //prepare the largest image copy($source, $target); $target
public function useImage($image, $photoid){
$source = $image['tmp_name'];
$target = "projectimages/";
//prepare the largest image
copy($source, $target);
$targetname = $photoid."large.jpg";
$file = $target.$targetname;
list($width, $height) = getimagesize($file);
$modwidth = 800;
$diff = $width / $modwidth;
$modheight = $height / $diff;
$tn = imagecreatetruecolor($modwidth, $modheight);
$image = imagecreatefromjpeg($file);
imagecopyresampled($tn, $image, 0, 0, 0, 0, $modwidth, $modheight, $width, $height);
imagejpeg($tn, $file, 100);
//prepare the smaller image
move_uploaded_file($source, $target);
$targetname = $photoid."small.jpg";
$file = $target.$targetname;
list($width, $height) = getimagesize($file);
$modwidth = 400;
$diff = $width / $modwidth;
$modheight = $height / $diff;
$tn = imagecreatetruecolor($modwidth, $modheight);
$image = imagecreatefromjpeg($file);
imagecopyresampled($tn, $image, 0, 0, 0, 0, $modwidth, $modheight, $width, $height);
imagejpeg($tn, $file, 100);
}
我遇到了很多错误,但其他错误的关键是我尝试复制或移动上传文件时的第一个错误
Warning: copy(projectimages/) [function.copy]: failed to open stream: Is a directory in /Applications/MAMP/htdocs/bs/classes/image.php on line 171
我在图像上使用了var_dump,看起来图像已经就位了
有什么想法吗?调用
copy()
的目标是一个目录。尝试按以下方式更改代码:
$source = $image['tmp_name'];
$target = "projectimages/";
//prepare the largest image
$targetname = $photoid."large.jpg";
$file = $target.$targetname;
copy($source, $file);
// The rest of your code goes here.
您必须在目标中包含文件名:copy('src/image.jpg','dest/newname.jpg')是的,修复了它,但是现在内存耗尽了!我们必须就此提出一个单独的问题。