Php 如何汇总数组中重复项的值？

对不起我的英语

你好，我解决不了这个问题，请帮忙。有一个数组：

array(
    (int) 0 => array(
        'player_id' => '1',
        'count_goals' => (int) 1
    ),
    (int) 1 => array(
        'player_id' => '2',
        'count_goals' => (int) 1
    ),
    (int) 2 => array(
        'player_id' => '1',
        'count_goals' => (int) 1
    )
)

结果应该是：

array(
    (int) 0 => array(
        'player_id' => '1',
        'count_goals' => (int) 1
    ),
    (int) 1 => array(
        'player_id' => '2',
        'count_goals' => (int) 1
    ),
    (int) 2 => array(
        'player_id' => '1',
        'count_goals' => (int) 1
    )
)

---

如果玩家id在数组中没有唯一的数字，则将其count\u goals增加1。

您基本上想要分组和求和：

$result = [];
foreach ($input as $row) {
    if (!isset($result[$row['player_id']])) {
        $result[$row['player_id']] = 0;
    }
    $result[$row['player_id']] += $result[$row['count_goals']];
}

这将为您提供如下数组：

[
   1 => 2, // player_id => sum of count_goals
   2 => 1,
]

然后，如果需要，可以将其转换回关联数组

$finalResult = [];
foreach ($result as $playerId => $sumOfGoals) {
     $finalResult[] = [
         'player_id' => $playerId,
         'count_goals' => $sumOfGoals,
     ];
}

print_r($finalResult);

---

我假设你想为每个球员的目标求和？：）@罗伯特（你理解得对）@Alex结果块不应该显示进球总数吗？现在两个代码块显示相同的数组？我添加了一个答案，但我不确定您的意思：

如果玩家id在数组中没有唯一的数字，那么将其count\u goals增加1。

设置count\u goals时？我的猜测是，只是想用输入的数字来增加它？