Php 组合顺序日期

我的表格中有以下数据

根据轮班id，我希望合并轮班日期

简而言之，我需要以下输出：

**output format : FromDate To ToDate (Shift_id)**

2012-12-01 To 2012-12-02 (2)

2012-12-03 (1)

2012-12-04 (2)

2012-12-18 To 2012-12-20 (1)

2012-12-21 To 2012-12-22 (2)

2012-12-23 To 2012-12-24 (1)

2012-12-25 To 2012-12-30 (2)

我尝试了几件事，但没有成功。任何人请帮助/指导我解决这个问题

我写了这段代码

    while($row_shift = mysql_fetch_object($result_shift)) {
    $new_date = $row_shift->shift_date;
    $new_shift = $row_shift->shift_id;
    if($new_shift !== $old_shift) {
        $shift_name = $new_shift;
        $shift_date_1 =  date('D d M',strtotime($new_date))." (".$shift_name.")";               
    } else {
        $shift_name = $old_shift;
        $shift_date_1 =  date('D d M',strtotime($old_date))." (".$shift_name.")";
        $diff = abs(floor( (strtotime($new_date) - strtotime($old_date)) / 3600 / 24));
        if($diff == 1) {                    
            $to_part = ' To ';
            $shift_date_2 = date('D d M',strtotime($new_date))." (".$shift_name.")";

        } else {
            $to_part = ' To ';
            $shift_date_2 = date('D d M',strtotime($old_date))." (".$shift_name.")";    
        }
    }

    $s_d_2 = $to_part.$shift_date_2;

    $shift_date[] = $shift_date_1.$s_d_2;

    $old_date = $row_shift->shift_date;
    $old_shift = $row_shift->shift_id;

}
echo implode("<br/>", $shift_date);

谢谢。

这是一个

---

您应该解释您在哪里面临问题，以及您尝试了什么这是非常容易使用循环的。只需从数据库中获取日期，并在for或foreach循环中进行迭代即可。@SashiKant我更新了我的问题。嘿，valex，我正试图理解你的查询。你能解释一下吗？

Output : 
Sat 01 Dec (2)
Sat 01 Dec (2) To Sun 02 Dec (2)
Mon 03 Dec (1)Sun 02 Dec (2)
Tue 04 Dec (2)Sun 02 Dec (2)
Tue 18 Dec (1)Sun 02 Dec (2)
Tue 18 Dec (1) To Wed 19 Dec (1)
Wed 19 Dec (1) To Thu 20 Dec (1)
Fri 21 Dec (2)Thu 20 Dec (1)
Fri 21 Dec (2) To Sat 22 Dec (2)
Sun 23 Dec (1)Sat 22 Dec (2)
Sun 23 Dec (1) To Mon 24 Dec (1)
Tue 25 Dec (2)Mon 24 Dec (1)
Tue 25 Dec (2) To Wed 26 Dec (2)
Wed 26 Dec (2) To Thu 27 Dec (2)
Thu 27 Dec (2) To Fri 28 Dec (2)
Fri 28 Dec (2) To Sat 29 Dec (2)
Sat 29 Dec (2) To Sun 30 Dec (2)

select min(shift_date) start_data,max(shift_date) end_date,
          min(Shift_id) Shift_id
from
(
select t.*,if(shift_id<>@CurShift,@i:=@i+1,@i) Group_num,
       @CurShift:=shift_id 
from t, (select @CurShift:=0,@i:=0) t1 
order by shift_date
 ) b

group by Group_num
order by Group_num