PHP MySQL插入不'；我不能工作，我可以'；我没有发现任何错误

我有这个PHP代码，我正试图将数据插入我的数据库。它似乎不起作用，我也不知道为什么。我试图回显mysqli_错误，但没有显示任何错误。我也响应了这个查询，当我直接在phpmyadmin中运行它时，它工作得很好

表格

<form method="POST" action="images.php?#werk" enctype="multipart/form-data">
                    <h6>Voeg nieuwe afbeelding toe</h6>
                    <div class="file-field input-field">
                        <div class="btn">
                            <span>Bestand</span>
                            <input name="install" type="file">
                        </div>
                        <div class="file-path-wrapper">
                            <input class="file-path validate" type="text">
                        </div>
                    </div>

                    <div class="input-field">
                        <textarea id="textarea1" name="caption" class="materialize-textarea"></textarea>
                        <label for="textarea1">Beschrijving</label>
                    </div>
                    <div class="row">
                        <button class="btn waves-effect waves-light" type="submit" name="submit2">Voeg toe
                            <i class="material-icons right">add</i>
                        </button>
                    </div>
                </form>

connect.php

$conn = mysqli_connect($server, $usernameDB, $password, $usernameDB);

// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

附加安装

function addInstallation($caption, $name){
$target_dir = "../in-progress.johnkok.com/img/installations/";
if($_FILES[$name]["size"] > 0){
    $target_file = $target_dir . basename($_FILES[$name]["name"]);
    $uploadOK = 1;
    $image_type = strtolower(pathinfo($target_file, PATHINFO_EXTENSION));
    $check = getimagesize($_FILES[$name]["tmp_name"]);

    if($check !== false){
        $uploadOK = 1;
    }
    else{
        $feedback2 = "Bestand is geen afbeelding.";
        $uploadOK = 0;
    }

    if($uploadOK !== 0){
        move_uploaded_file($_FILES[$name]["tmp_name"], $target_file);
        $target_file = "img/installations/" . basename($_FILES[$name]["name"]);
        $query = mysqli_query($conn, "INSERT INTO `Installations`(`caption`, `image_path`) VALUES ('$caption','$target_file')");
    }
}
mysqli_close($conn);

---

}

在php文件中，将$conn变量添加到传递的内容中

include "includes/connect.php";
if(isset($_POST['submit2'])){
addInstallation($_POST['caption'], "install",$conn);
}

---

在附加安装文件中包括连接文件。 例如：

include "includes/connect.php";
function addInstallation($caption, $name){
// some code
}

---

您确定您的脚本通过了条件“if（$uploadOK！==0）”吗？出现了什么错误？move\u uploaded\u文件似乎工作正常您没有向函数公开

$conn

变量。您对mysqli_查询的调用可能失败，但您从未检查错误。您调试过查询吗？我的意思是不使用mysqli_query（）的echo$query。并将该查询回传到数据库。

include "includes/connect.php";
function addInstallation($caption, $name){
// some code
}