将多个数据从Android发布到PHP web服务

到目前为止，我可以从Android向PHP web服务发送一组数据。我希望发送一个数组，并在web服务中有一个for循环。可能吗？这是一个好的解决方案吗？在这个项目中，我尝试将SQLite与MySQL同步

这是我的密码

String username, userid;
    username = "Kate";
    userid = "3";
    String data = "";

    try {
        data = URLEncoder.encode("username", "UTF-8") + "="
                + URLEncoder.encode(username, "UTF-8");
        data += "&" + URLEncoder.encode("userid", "UTF-8") + "="
                + URLEncoder.encode(userid, "UTF-8");
    } catch (UnsupportedEncodingException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    String text = "";
    BufferedReader reader = null;

    try {

        URL url = new URL(
                address);

        URLConnection conn = url.openConnection();
        conn.setDoOutput(true);
        OutputStreamWriter wr = new OutputStreamWriter(
                conn.getOutputStream());
        wr.write(data);
        wr.flush();

        // Get the response
        reader = new BufferedReader(new InputStreamReader(
                conn.getInputStream()));
        StringBuilder sb = new StringBuilder();
        String line = null;

        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        text = sb.toString();
    } catch (Exception ex) {

    } finally {
        try {
            reader.close();
        } catch (Exception ex) { }
    }

还有这个

<?php 
include '../inc/connect.php';
include '../inc/class/mysql.class.php'; 

$name   = urldecode($_POST['username']);
$user   = urldecode($_POST['userid']);

print " ==== POST DATA =====
Name  : $name
Email : $email
User  : $user
Pass  : $pass";

$ins = mysql_query("INSERT INTO users (UserName, FullName) VALUES ('$name','$user')") or die(mysql_error());
if ($ins) {
    echo json_encode(array("result"=>"success","result_txt"=>"Branch sucessfully added."));
    exit();
}
?>

---

您可以将输入作为JSON发送，然后让PHP对其进行解码

因此，您可以在android应用程序中对所有数据进行编码，并将其作为一个大的编码字符串发送，可能使用URI编码或Base64，然后在PHP中执行以下操作：

$data = json_decode($_POST['data']);

如果使用base64，则需要执行以下操作：

$data = json_decode(base64_decode($_POST['data']));

如果您只是将其作为一个字符串发送

$data = json_decode(urldecode($_POST['data']));