Php 未获取symfony中authenticationUtils的身份验证错误

我在Symfony 4中登录我的应用程序时遇到身份验证错误问题。 我可以与所有用户完美地登录，但当我试图故意登录失败时，我不会收到任何错误消息，$error也不会填充。这里我发布了我的LoginFormAuthenticator和securityController的代码。 LoginFormAuthenticator

    class LoginFormAuthenticator extends AbstractFormLoginAuthenticator
{
    /**
     * @var UserRepository
     */
    private $userRepository;
    /**
     * @var RouterInterface
     */
    private $router;
    /**
     * @var CsrfTokenManagerInterface
     */
    private $csrfTokenManager;
    /**
     * @var UserPasswordEncoderInterface
     */
    private $passwordEncoder;

    public function __construct(UserRepository $userRepository, RouterInterface $router, CsrfTokenManagerInterface $csrfTokenManager, UserPasswordEncoderInterface $passwordEncoder)
    {
        $this->userRepository = $userRepository;
        $this->router = $router;
        $this->csrfTokenManager = $csrfTokenManager;
        $this->passwordEncoder = $passwordEncoder;
    }
    public function supports(Request $request)
    {
        return $request->attributes->get('_route') === 'app_login'
            && $request->isMethod('POST');
    }

    public function getCredentials(Request $request)
    {
        $credentials = [
            'cargo' => $request->request->get('cargo'),
            'password' => $request->request->get('password'),
            'csrf_token' => $request->request->get('_csrf_token'),
        ];

        $request->getSession()->set(
            Security::LAST_USERNAME,
            $credentials['cargo']
        );

        return $credentials;
    }

    public function getUser($credentials, UserProviderInterface $userProvider)
    {
        $token = new CsrfToken('authenticate', $credentials['csrf_token']);
        if (!$this->csrfTokenManager->isTokenValid($token)) {
            throw new InvalidCsrfTokenException();
        }
        return $this->userRepository->findOneBy(['cargo' => $credentials['cargo']]);
    }

    public function checkCredentials($credentials, UserInterface $user)
    {
        return $this->passwordEncoder->isPasswordValid($user, $credentials['password']);
    }

    public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
    {
        // todo
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token, $providerKey)
    {
        return new RedirectResponse($this->router->generate('app_homepage'));
    }

    public function start(Request $request, AuthenticationException $authException = null)
    {
        // todo
    }

    public function supportsRememberMe()
    {
        // todo
    }

    protected function getLoginUrl()
    {
        return $this->router->generate('app_login');
    }
}

登录功能：

/**
     * @Route("/login", name="app_login")
     */
    public function login(AuthenticationUtils $authenticationUtils)
    {
        // get the login error if there is one
        $error = $authenticationUtils->getLastAuthenticationError();
        // last username entered by the user
        $lastUsername = $authenticationUtils->getLastUsername();

        return $this->render('security/login.html.twig', [
            'last_username' => $lastUsername,
            'error'         => $error,
        ]);
    }

登录HTML小枝

<form class="form-signin" method="post">
        {% if error %}
            <div class="alert alert-danger">{{ error.messageKey|trans(error.messageData, 'security') }}</div>
            <h3>{{ error.messageKey }}</h3>
        {% endif %}

{%if错误%}
{{error.messageKey | trans（error.messageData，'security'）}
{{error.messageKey}}
{%endif%}

---

谢谢

onAuthenticationFailure方法为空。请参阅parent:：onAuthenticationFailure。

---

方法应该返回响应对象。

只需注释掉onAuthenticationFailure方法，让父类处理它。如果您确实有编写自己的代码的冲动，那么请检查父代码，看看它需要做什么。