Php 返回以Yii表示的CActiveDataProvider

我有4个数据库表：

用户：id、用户名、密码

楼层：id、用户id、名称

房间：身份证、楼层、姓名

学生：id、房间、姓名、活动

如何为follow SQL命令返回cactivedaptaprovider

SELECT * FROM `student` WHERE `student`.`active` = 0 AND `student`.`room` IN (SELECT `room`.`id` FROM `room` WHERE `room`.`floor` = (SELECT `floor`.`id` FROM `floor` WHERE `floor`.`userid` = $userid))

我试过：

$model = Student::model()->findAllBySql("SELECT * FROM student WHERE active = 0 AND room IN (SELECT id FROM room WHERE floor = (SELECT id FROM floor WHERE user = $user))");
return new CActiveDataProvider($model);

但答复是：

致命错误：在第225行的X:appserv\www\framework\web\CActiveDataProvider.php中对非对象调用成员函数getDbCriteria

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命名占位符很有用

$criteria = new CDbCriteria;
$criteria->condition = 'student.active = 0 AND student.room IN (SELECT room.id FROM room WHERE room.floor = (SELECT floor.id FROM floor WHERE floor.userid = :userid))';
$criteria->params=array(':userid'=>$userid);
$dataProvider = new CActiveDataProvider('Student',array('criteria'=>$criteria,));

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谢谢，但是应该将$criteria->condition编辑为$criteria->condition=