Php 将2个表中的值传递给视图代码点火器

我有一个功能，将显示买卖清单。我试图在一页中显示这两个。 我从两个不同的表中获取值，并希望将这两个值传递到同一个模板中

有人能建议怎么做吗

控制器

function leads(){
    $this->load->model('listings');

    $data['mylists']=$this->member_functions->mine();
    $data['mylists2']=$this->member_functions->mine();

    $data['heading']='headings/heading_view';
    $data['body']='listbody';
    $data['nav']='right';

    $this->load->view('includes/template',$data);

}

型号

 function mine(){

    $mylists=$this->db->get('buy');

    if ($mylists->num_rows()>0){

        foreach ($mylists->result() as $a)
        {

            $data[]=$a;

        }
        return $data;
    }

    $mylists2=$this->db->get('sell');

    if ($mylists2->num_rows>0)
    {
        foreach ($mylists->result() as $b)
        {
            $data[]=$b;

        }

        return $data;

    }

}

查看

  <h2>Buy leads</h2>
                 <?php foreach ($mylists as $mylist):?>
         <p><?php echo "$mylist->type1 in $mylist->country as $mylist->buyid" ?></p>

       <?php endforeach;?>
            </div>
        <br />
            <h2>Sell leads</h2>
            <?php foreach ($mylists2 as $mylist2):?>
        <p><?php echo "$mylist2->type1 in $mylist2->country" ?></p>

       <?php endforeach;?>

购买线索



销售线索

不能在同一个函数中使用两个return语句，因为每当遇到第一个语句时，函数都会返回并停止。请尝试返回包含两个结果的单个数组，例如：

型号：

function mine(){

    $mylists=$this->db->get('buy');

    if ($mylists->num_rows()>0){

        foreach ($mylists->result() as $a)
        {
            $data['res1'][]=$a;
        }
    }

    $mylists2=$this->db->get('sell');

    if ($mylists2->num_rows>0)
    {
        foreach ($mylists->result() as $b)
        {
            $data['res2'][]=$b;
        }
    }
  return $data;
}

控制器：

$data['lists']=$this->member_functions->mine();

在您看来，这个数组应该像

$lists['res1']

adn

$lists['res2']