Php 在div或自定义位置显示查询？

如何将数据库连接信息放在页面顶部，但将查询与代码分开，但仍保持关联，以便打印或回送在Div中显示检索到的图像，并将其放置在网站的任何位置

<?php
$db = new PDO('mysql:host=host;dbname=dbname;charset=UTF-8', 'username', 'password');
$q = "SELECT badge1 FROM user_badges WHERE username='{$_SESSION['username']}' LIMIT 1";
$r = mysql_query($q);
$row = mysql_fetch_assoc($r);
$badge1 = $row['badge1'];

if($badge1 == "unlocked") {
 print "image if user has unlocked the badge";
  } else {
 print "image if user hasn't unlocked the badge";
}

?>

---

有两种方法。以下是一个例子：

<?php
$db = new PDO('mysql:host=host;dbname=dbname;charset=UTF-8', 'username', 'password');
$q = "SELECT badge1 FROM user_badges WHERE username='{$_SESSION['username']}' LIMIT 1";
$r = mysql_query($q);
$row = mysql_fetch_assoc($r);
$badge1 = $row['badge1'];
?> 

//Break out of PHP and add any HTML elements you want

<div id="whatever">

<?php
if($badge1 == "unlocked") {
    print "image if user has unlocked the badge";
} else {
    print "image if user hasn't unlocked the badge";
}
?>
</div>

//跳出PHP，添加任何想要的HTML元素
非常好，非常感谢！还感谢您注意到旧的msql_33;！我会处理的：）