Php 上载图像的名称

我正在把图片的名字上传到数据库

问题是名称在数据库中，名称前有一个空格

问题在哪里

$original_name = strtolower(trim($arquivo['name']));
$caracteres = array("ç","~","^","]","[","{","}",";",":","´",",",">",
                   "<","-","/","|","@","$","%","ã","â","á","à","é",
                  "è","ó","§","ò","+","=","*","&","(",")","!","#","?",
                  "`","ã"," ","©","£");

$original_name = str_replace(' ', '', $original_name);
$final_name = str_replace($caracteres,"",$original_name);

$original_name=strtolower（trim（$arquivo['name']）；
$caracteres=array（“ç”、“~”、“^”、“]”、“[”、“{”、“}”、“；”、“：”、“'）、“、”、“>”，
“我建议使用白名单中允许的字符，如
[a-zA-Z0-9.]

和使用：

$final_name = preg_replace("#[^a-z0-9_]+#i", "", $arquivo['name']);

你能给我们看一下在数据库中插入记录的查询吗？mysql_查询（“插入arquivos（nome，tipo，data，hora，item）值（“$final_name.”，“$tipo_arquivo.”，“$tipo_arquivo.”，CURDATE（），NOW（），“$idItem.”）；谢谢你，但是我添加了它，并且是相等的。然后，你在将值插入dbmysql_查询（“插入arquivos”）时添加了那个空格（nome，tipo，data，hora，item）值（“$final_name.”，“$tipo_arquivo.”，CURDATE（），NOW（），“$idItem.”）；