Php 多个While循环将第一个数据替换为第二个数据

我下面的代码有问题

我想显示与$jid的ID无关的数据，但我认为我的循环有问题。显示的第一个数据将被删除并替换为最后一个结果

这是密码。有人能帮我一下吗

$check\U exist\U query=mysql\U query（“从物理能力\U分配中选择*，其中作业\U title\U id=$jid”）

while（$check\u exist\u row=mysql\u fetch\u array（$check\u exist\u query））{
$list=“”；
$physical_title_id=$check_exist_row['2']；
if（空（$physical_title_id））{
$display\u abilities\u query=“选择*来自物理能力”；
}否则{
$display\u abilities\u query=“从物理能力中选择*，其中id！=$physical\u title\u id”；
}
$display\u abilities\u result=mysql\u query（$display\u abilities\u query）；
而（$display\u abilities\u row=mysql\u fetch\u array（$display\u abilities\u result））{
$abilities\u name=$display\u abilities\u行[2]；
$abilities\u id=$display\u abilities\u行[0]；
$list.=”
“$U名称。”
";

}

$list=”“；
$check\U exist\U query=mysql\U query（“从物理能力\U分配中选择*，其中作业\U title\U id=$jid”）；
而（$check\u exist\u row=mysql\u fetch\u array（$check\u exist\u query））{
$physical_title_id=$check_exist_row['2']；
if（空（$physical_title_id））{
$display\u abilities\u query=“选择*来自物理能力”；
}否则{
$display\u abilities\u query=“从物理能力中选择*，其中id！=$physical\u title\u id”；
}
$display\u abilities\u result=mysql\u query（$display\u abilities\u query）；
而（$display\u abilities\u row=mysql\u fetch\u array（$display\u abilities\u result））{
$abilities\u name=$display\u abilities\u行[2]；
$abilities\u id=$display\u abilities\u行[0]；
$list.=”
“$U名称。”
";
}
echo$列表；

试试这个

while($check_exist_row = mysql_fetch_array($check_exist_query)){
$list = "";
 $physical_title_id = $check_exist_row['2'];


if(empty($physical_title_id)){

    $display_abilities_query = "SELECT * FROM physical_abilities";
}else{

    $display_abilities_query = "SELECT * FROM physical_abilities WHERE id != $physical_title_id";
}

$display_abilities_result = mysql_query($display_abilities_query);

while($display_abilities_row = mysql_fetch_array($display_abilities_result)){

$abilities_name = $display_abilities_row[2];
  $abilities_id = $display_abilities_row[0];

$list .= "<tr>
                    <td $bgcolor align=center><input type=\"checkbox\" ".$check." name=\"job_title[]\" value=".$title_id." id=\"".$title_id."\"></td>
                    <td $bgcolor style=\"padding-left:5px;\">".$abilities_name."</td>
                    <td $bgcolor align=center><a onClick=\"return confirm('Are you sure you want to delete this entry?');\" href=?do=delete&id=". $row[0] ."><img src=\"images/delete-icon.png\" border=0 ></a>&nbsp;&nbsp;&nbsp;<a href=\"physical-abilities.php?id=$row[0]\"><img src=\"images/edit-icon.png\" title=\"Edit This\" border=0/></a></td>
       </tr>";

$list = "";
$check_exist_query = mysql_query("SELECT * FROM physical_abilities_assignment where job_title_id = $jid");

while($check_exist_row = mysql_fetch_array($check_exist_query)){

 $physical_title_id = $check_exist_row['2'];


if(empty($physical_title_id)){

    $display_abilities_query = "SELECT * FROM physical_abilities";
}else{

    $display_abilities_query = "SELECT * FROM physical_abilities WHERE id != $physical_title_id";
}

$display_abilities_result = mysql_query($display_abilities_query);

while($display_abilities_row = mysql_fetch_array($display_abilities_result)){

$abilities_name = $display_abilities_row[2];
  $abilities_id = $display_abilities_row[0];

$list .= "<tr>
                    <td $bgcolor align=center><input type=\"checkbox\" ".$check." name=\"job_title[]\" value=".$title_id." id=\"".$title_id."\"></td>
                    <td $bgcolor style=\"padding-left:5px;\">".$abilities_name."</td>
                    <td $bgcolor align=center><a onClick=\"return confirm('Are you sure you want to delete this entry?');\" href=?do=delete&id=". $row[0] ."><img src=\"images/delete-icon.png\" border=0 ></a>&nbsp;&nbsp;&nbsp;<a href=\"physical-abilities.php?id=$row[0]\"><img src=\"images/edit-icon.png\" title=\"Edit This\" border=0/></a></td>
       </tr>";
}

echo $list;