我可以在php中查询这个数组以生成结果吗？还是应该在MySQL中进行查询？

在下面的数组中，我收集了一个结果表中的数据。此数据显示用户击败最多的玩家，无论是玩家1还是玩家2

[[{"player2_id":"31","player2_name":"Jamie Charles"},
{"player2_id":"31","player2_name":"Jamie Charles"},
{"player2_id":"31","player2_name":"Jamie Charles"},
{"player2_id":"31","player2_name":"Jamie Charles"},
{"player2_id":"31","player2_name":"Jamie Charles"},
{"player1_id":"31","player1_name":"Jamie Charles"},
{"player1_id":"31","player1_name":"Jamie Charles"},
{"player1_id":"31","player1_name":"Jamie Charles"},
{"player1_id":"32","player1_name":"steve downs"},   
{"player1_id":"31","player1_name":"Jamie Charles"}]]

如您所见，playerX\u id:31出现9次，5次为player2\u id，4次为player1\u id

（为了得到这个表，我必须运行2次查询，并将两个结果添加到表中——一个用于所讨论的用户为玩家1时，另一个用于用户为玩家2时）

基本上，我想从这些数据中做的就是看看什么

playerX_id

出现得最多，并取相应的名称

因此，我希望的输出是

Jamie Charles

我可以从这个数组中执行此操作，还是应该在MySQL级别执行此操作

这是我的桌子：

+----------------+-------------+------+-----+---------+----------------+
|字段|类型|空|键|默认|额外|
+----------------+-------------+------+-----+---------+----------------+
|结果| id | int（11）| NO | PRI | NULL |自动增量|
|社区| id | int（11）| NO | | NULL ||
|player1|u id | int（11）| NO | | NULL ||
|玩家1|u name | varchar（50）| NO | | NULL ||
|球员1队|瓦尔查尔（50）|否| |空||
|球员1球|内线（11）|无| |空||
|player1|u结果| varchar（3）|否| |空||
|球员2球|内线（11）|无| |空||
|player2|u结果| varchar（3）|否| |空||
|player2|u id | int（11）| NO | | NULL ||
|玩家2|u name | varchar（50）| NO | | NULL ||
|球员2队|瓦尔查尔（50）|否| |空||
|播放者1|u pts | int（11）| NO | | NULL ||
|播放者2分整（11）无空|
|日期|日期|否|空||
+----------------+-------------+------+-----+---------+----------------+

这是我的MySQL查询：

public function getTotalMostWinsAgainst($playerId){

    $returnValue = array();
    $sql = "SELECT player2_id, player2_name FROM `results` WHERE player1_id = '".$playerId."' AND player1_result = 'W'";

$result = $this->conn->query($sql);
    if($result != null && (mysqli_num_rows($result) >= 1)){
while($row = $result -> fetch_array(MYSQLI_ASSOC)){
   if(!empty($row)){
      $returnValue[] = $row;
   }
}
}

$sql = "SELECT player1_id, player1_name FROM `results` WHERE player2_id = '".$playerId."' AND player2_result = 'W'";

$result = $this->conn->query($sql);
    if($result != null && (mysqli_num_rows($result) >= 1)){
while($row = $result -> fetch_array(MYSQLI_ASSOC)){
 if(!empty($row)){
    $returnValue[] = $row;
   }
}
}
    return $returnValue;
} 


}

尝试：

---

这将根据玩家1获胜时最像玩家2的名称给出第一个结果顺序，反之亦然

您还可以显示数据库结构或查询吗？似乎只需一个查询就可以做到这一点

select member, count(*) Total
from 
(
select player2_name as member
from results
WHERE player1_id = 2 AND player1_result = 'W'
union all
select player1_name
from results
WHERE player2_id = 2 AND player2_result = 'W'

) AS T

group by member
order by Total desc
Limit 1