Php 主题更新失败

一切正常，我在编写代码时没有收到任何语法错误（我使用的是Dreamviwer代码编辑器软件。但是，当我运行它时，我收到以下错误： //处理表格

    Subject Update Failed!!You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' at line 1
I am stuck here can anyone help me what I am missing in this code.The error is in Update Query.

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很可能您输入了错误的参数名称。请先输入您的参数

并使用准备好的语句来防止SQL注入：

    $id= $current_subject["Id"];
$name=mysql_prep($_POST["Name"]);
$position=(int)$_POST["Position"];
$visible=(int)$_POST["Visible"];

$query="UPDATE subjects SET Name='{$name}',Position=$position,Visible=$visible WHERE Id={$id}";

$result= mysqli_query($conn, $query);
if($result && mysqli_affected_rows($conn)==1){
    //success
    $_SESSION["message"]="Subject updated.";
    redirect_to("manage_content.php");

}else{

    //Failure
   $message="Subject Update Failed" . $conn->error;

    }

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进一步阅读：。

什么是mysql_prep？我认为您需要删除更新查询

echo$query

中的{}。当您发现语法错误时，请卷起尾巴。

$dbh = new PDO('mysql:host=localhost;dbname=test', $user, $pass);
$query="UPDATE subjects SET Name = ? ,Position = ?,Visible = ? WHERE Id = ?";
$stmt = $dbh->prepare($query);
$stmt->bindParam(1, $name);
$stmt->bindParam(2, $position);
$stmt->bindParam(3, $visible);
$stmt->bindParam(4, $id);
$stmt->execute();
$stmt->fetchAll();