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php代码:计算oracle sql中的行数_Php_Oracle_Login - Fatal编程技术网

php代码:计算oracle sql中的行数

php代码:计算oracle sql中的行数,php,oracle,login,Php,Oracle,Login,我尝试编写一个logIn.php。但行数始终返回0。谢谢你的帮助 $sql = "SELECT COUNT(*) as c FROM users WHERE '.password.' = '.$password.' AND '.name.' = '.$username.'"; $stid = oci_parse($dbh, $sql); oci_execute($stid); oci_fetch_all($stid, $resul

我尝试编写一个logIn.php。但行数始终返回0。谢谢你的帮助

       $sql = "SELECT COUNT(*) as c FROM users WHERE '.password.' = '.$password.' AND '.name.' = '.$username.'";
       $stid = oci_parse($dbh, $sql);  
       oci_execute($stid);  

       oci_fetch_all($stid, $result);
       $row = $result['C'][0];
       echo $row;

请使用$sql=“SELECT COUNT(*)作为c从用户那里获得密码=“{$password}”和名称=“{$username}”;可能是您的sql出错,因此它始终返回0。还要使用错误处理。检查整个结果是什么(print_r($result);)哦,非常感谢。它起作用了!