Php 为个人用户显示表格

我正在尝试使用会话查看特定用户的数据。当我离开时，所有的细节都提到了 以personid=1的管理员身份登录。但当我尝试以独立用户身份登录时，表是 没有显示。我相信错误在代码的IFELSE部分。 我使用连接来组合多个表。Where语句的语法正确吗

  protected function selectAll() {

   try {                                                   

        $this->pdo = $this->Connect();            

         session_start();

本节用于查看管理员的所有班次

       if( isset($_SESSION["personid"]) && $_SESSION["personid"] === '1' ) { 
       $sql = "select * from PersonShift "                 
             . " inner join Person on Person.PersonID = PersonShift.PersonID"                 
             . " inner join Role on Role.RoleID = PersonShift.RoleID"
             . " inner join BusShift on BusShift.ShiftNo = PersonShift.ShiftNo";               

       }

在此部分中，登录用户只能看到其特定班次

        else if( isset($_SESSION["personid"]) && $_SESSION["personid"] !== '1' ) {

     $sql = "select * from PersonShift "                 
             . " inner join Person on Person.PersonID = PersonShift.PersonID"                 
             . " inner join Role on Role.RoleID = PersonShift.RoleID"
             . " inner join BusShift on BusShift.ShiftNo = PersonShift.ShiftNo"
             . "where PersonShift.PersonID = ".$_SESSION['personid'];  

        }                             

        $stmt = $this->pdo->prepare($sql);                        


        }                               

        $this->result = $stmt->fetchAll();                             

        $this->pdo = null;                        

        return $this->result;                                                

               } catch (\Exception $ex) {

               throw new \Exception($ex->getMessage());

       }                      

       }         

---

我发现了几个问题：首先，大括号没有正确匹配，因此代码有点不可预测；其次，我看不到您在哪里执行查询

请试试这个：

protected function selectAll() 
{
    try {                                                   
        $this->pdo = $this->Connect();            
        session_start();

        if( isset($_SESSION["personid"]) && $_SESSION["personid"] === '1' ) 
        { 
          $sql = "select * from PersonShift "                 
             . " inner join Person on Person.PersonID = PersonShift.PersonID"                 
             . " inner join Role on Role.RoleID = PersonShift.RoleID"
             . " inner join BusShift on BusShift.ShiftNo = PersonShift.ShiftNo";               
        }
        else if( isset($_SESSION["personid"]) && $_SESSION["personid"] !== '1' ) 
        {
            $sql = "select * from PersonShift "                 
                   . " inner join Person on Person.PersonID = PersonShift.PersonID"                 
                   . " inner join Role on Role.RoleID = PersonShift.RoleID"
                   . " inner join BusShift on BusShift.ShiftNo = PersonShift.ShiftNo"
                   . "where PersonShift.PersonID = ".$_SESSION['personid'];  

        } // end if 

        $stmt = $this->pdo->prepare($sql);

        $stmt->execute(); // Execute was missing

        //} This was misplaced

        $this->result = $stmt->fetchAll();                             

        $this->pdo = null;                        

        return $this->result;                                                

    } catch (\Exception $ex) {
        throw new \Exception($ex->getMessage());
    }                      
} // end function

---

还是没有结果你确定会话变量被正确填充了吗？你有没有试过直接对数据库进行这些查询，以确保它们产生预期的结果呢？你在。。。BUSHIFT.ShiftNo=人员换档.ShiftNo和。PersonShift.PersonID。。。因此，它将被解析为BusShift.ShiftNo=PersonShift.ShiftNowhere PersonShift.PersonID。添加一个空格->。PersonShift.PersonID。。。