Php 如何允许用户仅在工作时间登录？

我想制作一个限制用户在工作时间后登录的代码： 用户只能在8:00到4:35之间登录： 下面是我尝试过的代码，我设法使两个条件起作用，但第三个条件不起作用：任何帮助都将非常感谢：

<?php
    # function to get right time of the targeted city
    date_default_timezone_set('Africa/Johannesburg');
    function time_diff_conv($start, $s)
    {
        $string="";
        $t = array( //suffixes
            'd' => 86400,
            'h' => 3600,
            'm' => 60,
        );
        $s = abs($s - $start);
        foreach($t as $key => &$val) {
            $$key = floor($s/$val);
            $s -= ($$key*$val);
            $string .= ($$key==0) ? '' : $$key . "$key ";
        }
        return $string . $s. 's';
    }
$date = date('h:i');
 echo  $date;
 /*Start time for work*/
 $workStart = strtotime("08:00");//am
  /*Stop time for work*/
 $workStop = strtotime("04:35");//pm
 /*This is the current time*/
 $currentTime = strtotime($date); 
 //$fromSatrtToEnd = $workStart->diff($workStop);
 /*This Condition works*/
 if($currentTime >=$workStart){
 echo "Start Working";
 /*This Condition also  works*/
 } else if($currentTime < $workStart){
 echo "You too early at work";
 }
 /*This Condition does not works*/
 else if($currentTime < $workStop){
 echo "Its after work";
 }

?>

---

如果（$currentTime>=$workStart和$currentTime必须明确日期的时间段，则程序无法识别08:00是上午日期，04:35是下午日期

只需在中更改变量声明

 /*Start time for work*/
 $workStart = strtotime("08:00 AM");//am
  /*Stop time for work*/
 $workStop = strtotime("04:35 PM");//pm

或将第二个变量转换为24小时格式：

$workStop=strotime（“下午16:35”）；//下午

这样，与
$workStop
相比，
$workStart
将被正确评估为次要值

然后更改if以正确匹配条件：

if($currentTime >=$workStart && $current <= $workstop){
    echo "Start Working";
} else if($currentTime < $workStart){
    echo "You too early at work";
}
else if($currentTime > $workStop){ 
    echo "Its after work";
}

如果（$currentTime>=$workStart&&$current$workStop）{
回应“下班后”；
}
首先，如果您必须管理上午/下午的小时数，您应该在使用小时数的每一行中将其转换为24小时格式：

如果你的条件不合适，你应该有如下的条件：

if($currentTime >=$workStart AND $current <= $workstop){ // need to check both
    echo "Start Working";
} else if($currentTime < $workStart){
    echo "You too early at work";
}
else if($currentTime > $workStop){ // > rather than <
    echo "Its after work";
}

如果（$currentTime>=$workStart和$current$workStop）{/>而不是<
回应“下班后”；
}
当我把这个和$currentTime放在一起时，非常感谢我将Kawashita86的想法与你的代码结合起来，然后它起了作用，我真的很感激我希望我能胜过你：你做得很好，现在我的代码起作用了，这是为了与腰肉代码集成
$date = date('H:i'); // H rather than h
$workStart = strtotime("08:00");
$workStop = strtotime("16:35");

if($currentTime >=$workStart AND $current <= $workstop){ // need to check both
    echo "Start Working";
} else if($currentTime < $workStart){
    echo "You too early at work";
}
else if($currentTime > $workStop){ // > rather than <
    echo "Its after work";
}