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Php 适用于CI下拉列表的转换数组_Php_Arrays_Codeigniter - Fatal编程技术网

Php 适用于CI下拉列表的转换数组

Php 适用于CI下拉列表的转换数组,php,arrays,codeigniter,Php,Arrays,Codeigniter,我正在使用CodeIgniter方法(db->result\u array())返回以下数组: Array ( [0] => Array ( [id] => 5 [lang_name] => ASM ) [1] => Array ( [id] => 16 [lang_name] => Bash ) [2] => Array (

我正在使用CodeIgniter方法(db->result\u array())返回以下数组:

 Array
 (
[0] => Array
    (
        [id] => 5
        [lang_name] => ASM
    )

[1] => Array
    (
        [id] => 16
        [lang_name] => Bash
    )

[2] => Array
    (
        [id] => 17
        [lang_name] => Batch
    )

[3] => Array
    (
        [id] => 3
        [lang_name] => C
    )

[4] => Array
    (
        [id] => 11
        [lang_name] => C#
    )

[5] => Array
    (
        [id] => 4
        [lang_name] => C++
    )
 )
我需要一个具有这种格式的数组,将其传递给form_dropdown()CI函数:

 $atrLangDropDown = array(
    '1' => 'CPP',
    '2' => 'PHP',
    '3' => 'ASM'
);
我做过这样的事情:

public function getAllLangsSelect() {
    $this->db->select('*')->from($this->tableName)->order_by($this->tableName.'.lang_name');
    $q = $this->db->get();
    $data = array();
    array_push($data, '- Select Language -');

    foreach ($q->result_array() as $row) {  
        array_push($data, $row['lang_name']);
    }

    return $data;

}
但它必须保留存储在数据库中的原始ID,因此它不能正常工作

欢迎任何提示或帮助。这是我第一次做这种手术。

试试这个:

public function getAllLangsSelect()
{
    $query = $this->db
        ->order_by('lang_name')
        ->get($this->tableName);

    $options[''] = '- Select Language -';

    foreach ($query->result() as $row)
    {  
        $options[$row->id] = $row->lang_name;
    }

    return $options;
}

我刚做完,谢谢你。解决方案是:公共函数getAllLangsSelect(){$this->db->select('*')->from($this->tableName)->order\u by($this->tableName..lang\u name');$q=$this->db->get();$data=array();$tmp=$q->result\u array();for($i=0;$i