Php 将SQL转换为Eloquent以联接多个表并计数

我一直认为这个SQL工作得很好，但试图将其转换为雄辩的格式，它不断返回错误的SQL，这完全标志着错误。 使用Laravel 5.5进行编码

Select arm_articles.article_topic, arm_articles.id, arm_articles.article_id, 
COUNT(arm_article_views.view_article_id) AS TotalViews, 
COUNT( arm_article_likes.liked_article_id) AS TotalLikes, 
COUNT( arm_article_comments.comment_article_id) AS TotalComments
FROM arm_articles 
LEFT JOIN  arm_article_views  ON  arm_articles.article_id = arm_article_views.view_article_id 
LEFT JOIN  arm_article_likes  ON  arm_articles.article_id = arm_article_likes.liked_article_id 
LEFT JOIN  arm_article_comments  ON  arm_articles.article_id = arm_article_comments.comment_article_id 
GROUP BY arm_articles.article_id 
ORDER BY TotalLikes, TotalLikes, TotalComments ASC`

我是如何让雄辩的查询生成器无法工作的：

return Datatables::of(PostModel::leftJoin('arm_article_views', 'arm_article_views.view_article_id', '=', 'arm_articles.article_id')
       ->leftJoin('arm_article_likes','arm_article_likes.liked_article_id', '=', 'arm_articles.article_id')
       ->leftJoin('arm_article_comments', 'arm_article_comments.comment_article_id','=','arm_articles.article_id')
       ->selectRaw(
           'arm_articles.*, 
           count(arm_article_views.view_article_id) AS ViewCount'
        ) 
        ->groupBy('arm_articles.article_id')->orderBy('ViewCount','DESC')
        ->where('arm_articles.article_contributor_id','=',$contributor_id)
        ->getQuery())->make(true);

任何提示都将不胜感激

请尝试以下内容：

DB::table('arm_articles')
        ->leftJoin('arm_article_views', 'arm_articles.article_id', '=', 'arm_article_views.view_article_id')
        ->leftJoin('arm_article_likes', 'arm_articles.article_id', '=', 'arm_article_likes.liked_article_id')
        ->leftJoin('arm_article_comments', 'arm_articles.article_id', '=', 'arm_article_comments.comment_article_id')
        ->groupBy('arm_articles.article_id', 'article_topic')
        ->select(
            DB::raw('count(arm_article_views.view_article_id) as TotalViews'),
            DB::raw('count(arm_article_likes.liked_article_id) as TotalLikes'),
            DB::raw('count(arm_article_comments.comment_article_id) as TotalComments'),
            'arm_articles.article_id',
            'article_topic'
        )->get();

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@Nikola Gavric你有什么线索吗？我已经发布了一个答案，等待你看看它是否对你的答案起到了关键作用，但当我尝试在select->select'arm_articles.*上添加更多字段时，遇到了一些SQL错误，错误消息为SQLSTATE[42000]：语法错误或访问冲突：1055“knowledge\u db.arm\u articles.id”不在SQL分组中：选择arm\u articles.*，countarm\u article\u views.view\u article\u id为TotalViews，countarm\u article\u likes.liked\u article\u id为totalikes，countarm\u article\u comments.comment\a………db:：table'arm\u articles'->leftJoin'arm\u article\u views'，“arm文章.文章id'，'='，'arm文章视图.视图文章id'->leftJoin'arm文章喜欢'，'arm文章id'，'='，'arm文章喜欢'，'arm文章id'->leftJoin'arm文章评论'，'arm文章id'，'，'arm文章评论.评论文章id'->groupBy'arm文章.文章id'->选择'arm文章。*，DB:：raw'countarm\u article\u views.view\u article\u id as TotalViews'，DB:：raw'countarm\u article\u id as totalikes'，DB:：raw'countarm\u article\u comments.comment\u article\u id as….您正在按article\u id进行分组，因此无法使用*通配符->选择'arm\u articles.id'、'arm\u articles.articles\u id'、'arm\u articles.articles\u category\u id'，“arm_文章.文章主题”，“arm_文章.文章类型”，“arm_文章.文章日期”，“arm_文章.文章活动”，“arm_文章.文章类别”，“arm_文章.文章标记”，它返回了相同的错误，或者我如何将文章id和文章主题包含到SQLJust中的选定字段中？刚刚运行了更新的SQL并得到了错误SQLSTATE[42000]：语法错误或访问冲突：1055“knowledge\u db.arm\u articles.article\u topic”不在SQL分组中：选择countarm\u article\u views.view\u article\u id作为TotalViews，countarm\u article\u likes.liked\u article\u id作为Totalikes，=>似乎一旦将任何字段添加到select中，它就会标记