Php 将2个内部联接结果联接为一个结果
每个人我都有问题。我有两个查询,分别运行良好。但我想提出一个我已经尝试过的问题,但这些都不起作用。我需要连接两个输出 第一次查询:Php 将2个内部联接结果联接为一个结果,php,mysql,sql,join,mysqli,Php,Mysql,Sql,Join,Mysqli,每个人我都有问题。我有两个查询,分别运行良好。但我想提出一个我已经尝试过的问题,但这些都不起作用。我需要连接两个输出 第一次查询: SELECT q_internal_table.q_part_id, q_external_table.q_external_id, q_external_table.q_external_approve, q_external_table.q_order_id, q_internal_table.q_internal_id,
SELECT q_internal_table.q_part_id,
q_external_table.q_external_id,
q_external_table.q_external_approve,
q_external_table.q_order_id,
q_internal_table.q_internal_id,
q_internal_table.q_internal_approve
FROM (SELECT parts.id AS q_part_id,
parts.order_id AS q_order_id,
external_reports.id AS q_external_id,
external_reports.approved AS q_external_approve
FROM parts
INNER JOIN external_reports
ON( parts.id = external_reports.part_id ))
q_external_table
INNER JOIN (SELECT parts.id AS q_part_id,
internal_reports.id AS q_internal_id,
internal_reports.approved AS q_internal_approve
FROM parts
INNER JOIN internal_reports
ON( parts.id = internal_reports.part_id ))
q_internal_table
ON( q_external_table.q_part_id = q_internal_table.q_part_id )
WHERE ( q_external_table.q_external_approve = 'Y'
OR q_internal_table.q_internal_approve = 'Y' )
第二次查询:
SELECT q_five_internal_table.q_five_part_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve,
q_five_external_table.q_five_order_id
FROM (SELECT parts.id AS q_five_part_id,
parts.order_id AS q_five_order_id,
five_way_external_reports.id AS q_five_external_id,
five_way_external_reports.approved AS q_five_external_approve
FROM parts
INNER JOIN five_way_external_reports
ON( parts.id = five_way_external_reports.part_id ))
q_five_external_table
INNER JOIN (SELECT parts.id AS q_five_part_id,
five_way_internal_reports.id AS q_five_internal_id,
five_way_internal_reports.approved AS q_five_internal_approve
FROM parts
INNER JOIN five_way_internal_reports
ON( parts.id = five_way_internal_reports.part_id ))
q_five_internal_table
ON( q_five_external_table.q_five_part_id = q_five_internal_table.q_five_part_id )
WHERE ( q_five_external_table.q_five_external_approve = 'Y'
OR q_five_internal_table.q_five_internal_approve = 'Y' )
第一次查询结果:
第二次查询结果:
我尝试过这个查询:-
SELECT q_internal_external_table.*,
q_five_internal_external_table.*
FROM (SELECT q_internal_table.q_part_id,
q_external_table.q_external_id,
q_external_table.q_external_approve,
q_external_table.q_order_id,
q_internal_table.q_internal_id,
q_internal_table.q_internal_approve
FROM (SELECT parts.id AS q_part_id,
parts.order_id AS q_order_id,
external_reports.id AS q_external_id,
external_reports.approved AS q_external_approve
FROM parts
INNER JOIN external_reports
ON( parts.id = external_reports.part_id ))
q_external_table
INNER JOIN (SELECT parts.id AS q_part_id,
internal_reports.id AS q_internal_id,
internal_reports.approved AS q_internal_approve
FROM parts
INNER JOIN internal_reports
ON( parts.id = internal_reports.part_id ))
q_internal_table
ON( q_external_table.q_part_id = q_internal_table.q_part_id )
WHERE ( q_external_table.q_external_approve = 'Y'
OR q_internal_table.q_internal_approve = 'Y' ))
q_internal_external_table
INNER JOIN (SELECT q_five_internal_table.q_five_part_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve,
q_five_external_table.q_five_order_id,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve
FROM (SELECT parts.id AS q_five_part_id,
parts.order_id AS
q_five_order_id
,
five_way_external_reports.id AS
q_five_external_id,
five_way_external_reports.approved AS
q_five_external_approve
FROM parts
INNER JOIN five_way_external_reports
ON( parts.id = five_way_external_reports.part_id ))
q_five_external_table
INNER JOIN (SELECT parts.id AS q_five_part_id,
five_way_internal_reports.id AS
q_five_internal_id,
five_way_internal_reports.approved AS
q_five_internal_approve
FROM parts
INNER JOIN five_way_internal_reports
ON( parts.id = five_way_internal_reports.part_id ))
q_five_internal_table
ON ( q_five_external_table.q_five_part_id =
q_five_internal_table.q_five_part_id )
WHERE ( q_five_external_table.q_five_external_approve = 'Y'
OR q_five_internal_table.q_five_internal_approve = 'Y' ))
q_five_internal_external_table
ON ( q_internal_external_table.q_part_id =
q_five_internal_external_table.q_five_part_id )
查询结果:-
在这个查询中有三个结果。但是我希望7的结果和第一个查询结果一样。这三个答案已经出现在第一个查询结果中。我也需要休息。我认为问题出在q_internal_external_table.q_part_id=q_five_internal_external_table.q_five_part_id上的。但我不知道如何解决它
请帮帮我。提前谢谢。您需要的是工会
两个查询都需要具有相同的金额列和类型。在您的情况下,您需要更改所选列的顺序,以便使联合
应该是这样的:
SELECT q_internal_table.q_part_id,
q_external_table.q_external_id,
q_external_table.q_external_approve,
q_external_table.q_order_id,
q_internal_table.q_internal_id,
q_internal_table.q_internal_approve
FROM (SELECT parts.id AS q_part_id,
parts.order_id AS q_order_id,
external_reports.id AS q_external_id,
external_reports.approved AS q_external_approve
FROM parts
INNER JOIN external_reports
ON( parts.id = external_reports.part_id ))
q_external_table
INNER JOIN (SELECT parts.id AS q_part_id,
internal_reports.id AS q_internal_id,
internal_reports.approved AS q_internal_approve
FROM parts
INNER JOIN internal_reports
ON( parts.id = internal_reports.part_id ))
q_internal_table
ON( q_external_table.q_part_id = q_internal_table.q_part_id )
WHERE ( q_external_table.q_external_approve = 'Y'
OR q_internal_table.q_internal_approve = 'Y' )
UNION ALL
SELECT q_five_internal_table.q_five_part_id,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve,
q_five_external_table.q_five_order_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve
FROM (SELECT parts.id AS q_five_part_id,
parts.order_id AS q_five_order_id,
five_way_external_reports.id AS q_five_external_id,
five_way_external_reports.approved AS q_five_external_approve
FROM parts
INNER JOIN five_way_external_reports
ON( parts.id = five_way_external_reports.part_id ))
q_five_external_table
INNER JOIN (SELECT parts.id AS q_five_part_id,
five_way_internal_reports.id AS q_five_internal_id,
five_way_internal_reports.approved AS q_five_internal_approve
FROM parts
INNER JOIN five_way_internal_reports
ON( parts.id = five_way_internal_reports.part_id ))
q_five_internal_table
ON( q_five_external_table.q_five_part_id = q_five_internal_table.q_five_part_id )
WHERE ( q_five_external_table.q_five_external_approve = 'Y'
OR q_five_internal_table.q_five_internal_approve = 'Y' )
请注意,我已经更改了第二个查询中列的顺序,以匹配第一个查询的类型。您需要的是UNION
两个查询都需要具有相同的金额列和类型。在您的情况下,您需要更改所选列的顺序,以便使联合
应该是这样的:
SELECT q_internal_table.q_part_id,
q_external_table.q_external_id,
q_external_table.q_external_approve,
q_external_table.q_order_id,
q_internal_table.q_internal_id,
q_internal_table.q_internal_approve
FROM (SELECT parts.id AS q_part_id,
parts.order_id AS q_order_id,
external_reports.id AS q_external_id,
external_reports.approved AS q_external_approve
FROM parts
INNER JOIN external_reports
ON( parts.id = external_reports.part_id ))
q_external_table
INNER JOIN (SELECT parts.id AS q_part_id,
internal_reports.id AS q_internal_id,
internal_reports.approved AS q_internal_approve
FROM parts
INNER JOIN internal_reports
ON( parts.id = internal_reports.part_id ))
q_internal_table
ON( q_external_table.q_part_id = q_internal_table.q_part_id )
WHERE ( q_external_table.q_external_approve = 'Y'
OR q_internal_table.q_internal_approve = 'Y' )
UNION ALL
SELECT q_five_internal_table.q_five_part_id,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve,
q_five_external_table.q_five_order_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve
FROM (SELECT parts.id AS q_five_part_id,
parts.order_id AS q_five_order_id,
five_way_external_reports.id AS q_five_external_id,
five_way_external_reports.approved AS q_five_external_approve
FROM parts
INNER JOIN five_way_external_reports
ON( parts.id = five_way_external_reports.part_id ))
q_five_external_table
INNER JOIN (SELECT parts.id AS q_five_part_id,
five_way_internal_reports.id AS q_five_internal_id,
five_way_internal_reports.approved AS q_five_internal_approve
FROM parts
INNER JOIN five_way_internal_reports
ON( parts.id = five_way_internal_reports.part_id ))
q_five_internal_table
ON( q_five_external_table.q_five_part_id = q_five_internal_table.q_five_part_id )
WHERE ( q_five_external_table.q_five_external_approve = 'Y'
OR q_five_internal_table.q_five_internal_approve = 'Y' )
请注意,我已更改了第二个查询中列的顺序,以匹配第一个查询的类型。如果我们假设查询的最终目标是在下表中查找parts.id,则更新后的查询似乎是正确的(语义上):
外部报告、内部报告、五向外部报告、五向内部报告
在组合查询1和查询2的行时使用Union
但是,如果您试图查找匹配的列(join子句),则将使用join和not UNION
此外,请尝试解释并解释查询的扩展前缀,以了解查询计划。如果我们假设查询的最终目标是在下表中查找parts.id,则您更新的查询似乎是正确的(语义上):
外部报告、内部报告、五向外部报告、五向内部报告
在组合查询1和查询2的行时使用Union
但是,如果您试图查找匹配的列(join子句),则将使用join和not UNION
另外,请尝试解释并解释查询的扩展前缀,以了解查询计划。特别感谢@dnoeth。伟人
修改后的SQL是
select q_internal_external_table.*,q_five_internal_external_table.* from
(select q_internal_table.q_part_id,
q_external_table.q_external_id,q_external_table.q_external_approve,
q_external_table.q_order_id,q_internal_table.q_internal_id,
q_internal_table.q_internal_approve from(SELECT parts.id as
q_part_id,parts.order_id as q_order_id,external_reports.id as
q_external_id,external_reports.approved as q_external_approve from parts
LEFT join external_reports on(parts.id=external_reports.part_id))
q_external_table LEFT join (SELECT parts.id as q_part_id,internal_reports.id
as q_internal_id,internal_reports.approved as q_internal_approve from parts
LEFT join internal_reports on(parts.id=internal_reports.part_id))
q_internal_table on(q_external_table.q_part_id=q_internal_table.q_part_id)
where (q_external_table.q_external_approve='Y' or
q_internal_table.q_internal_approve='Y')) q_internal_external_table LEFT
join (select q_five_internal_table.q_five_part_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve,
q_five_external_table.q_five_order_id,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve from (SELECT parts.id as
q_five_part_id,parts.order_id as q_five_order_id,
five_way_external_reports.id as q_five_external_id,
five_way_external_reports.approved as q_five_external_approve from parts
LEFT join five_way_external_reports on(parts.id=
five_way_external_reports.part_id)) q_five_external_table LEFT join (SELECT
parts.id as q_five_part_id,five_way_internal_reports.id as
q_five_internal_id,five_way_internal_reports.approved as
q_five_internal_approve from parts LEFT join five_way_internal_reports
on(parts.id=five_way_internal_reports.part_id)) q_five_internal_table on
(q_five_external_table.q_five_part_id=q_five_internal_table.q_five_part_id)
where (q_five_external_table.q_five_external_approve='Y' or
q_five_internal_table.q_five_internal_approve='Y'))
q_five_internal_external_table on (q_internal_external_table.q_part_id
=q_five_internal_external_table.q_five_part_id)
答案:(我想要的)
特别感谢@dnoeth。伟人
修改后的SQL是
select q_internal_external_table.*,q_five_internal_external_table.* from
(select q_internal_table.q_part_id,
q_external_table.q_external_id,q_external_table.q_external_approve,
q_external_table.q_order_id,q_internal_table.q_internal_id,
q_internal_table.q_internal_approve from(SELECT parts.id as
q_part_id,parts.order_id as q_order_id,external_reports.id as
q_external_id,external_reports.approved as q_external_approve from parts
LEFT join external_reports on(parts.id=external_reports.part_id))
q_external_table LEFT join (SELECT parts.id as q_part_id,internal_reports.id
as q_internal_id,internal_reports.approved as q_internal_approve from parts
LEFT join internal_reports on(parts.id=internal_reports.part_id))
q_internal_table on(q_external_table.q_part_id=q_internal_table.q_part_id)
where (q_external_table.q_external_approve='Y' or
q_internal_table.q_internal_approve='Y')) q_internal_external_table LEFT
join (select q_five_internal_table.q_five_part_id,
q_five_internal_table.q_five_internal_id,
q_five_internal_table.q_five_internal_approve,
q_five_external_table.q_five_order_id,
q_five_external_table.q_five_external_id,
q_five_external_table.q_five_external_approve from (SELECT parts.id as
q_five_part_id,parts.order_id as q_five_order_id,
five_way_external_reports.id as q_five_external_id,
five_way_external_reports.approved as q_five_external_approve from parts
LEFT join five_way_external_reports on(parts.id=
five_way_external_reports.part_id)) q_five_external_table LEFT join (SELECT
parts.id as q_five_part_id,five_way_internal_reports.id as
q_five_internal_id,five_way_internal_reports.approved as
q_five_internal_approve from parts LEFT join five_way_internal_reports
on(parts.id=five_way_internal_reports.part_id)) q_five_internal_table on
(q_five_external_table.q_five_part_id=q_five_internal_table.q_five_part_id)
where (q_five_external_table.q_five_external_approve='Y' or
q_five_internal_table.q_five_internal_approve='Y'))
q_five_internal_external_table on (q_internal_external_table.q_part_id
=q_five_internal_external_table.q_five_part_id)
答案:(我想要的)
1)预期结果是什么?2) 你尝试过什么?这些尝试出了什么问题?你是说一个联盟-谷歌that@Shadow当前位置我更新了问题。我想加入这两个答案。我还添加了我尝试过的SQL。类似于select*from(1st select)作为t1连接(2nd select)作为t1.q\u part\u id=t2.q\u five\u part\u id
。连接意味着什么?请演示使用问题中已有的7+3记录。1)预期结果是什么?2) 你尝试过什么?这些尝试出了什么问题?你是说一个联盟-谷歌that@Shadow当前位置我更新了问题。我想加入这两个答案。我还添加了我尝试过的SQL。类似于select*from(1st select)作为t1连接(2nd select)作为t1.q\u part\u id=t2.q\u five\u part\u id
。连接意味着什么?请演示使用问题中已有的7+3记录。在不知道预期输出的情况下,它可能是一个联合
或,除了
或交叉
,也:-)感谢您的帮助。但是在回答中没有显示第二个查询结果。在不知道预期输出的情况下,它可能是一个联合
或,除了
或交叉
,也:-)感谢您的帮助。但在回答中,第二个查询结果没有显示。