MySql/PHP论坛选择要查看的论坛时出现问题
我有两个文件fourm.php和viewfourm.phpMySql/PHP论坛选择要查看的论坛时出现问题,php,html,mysql,phpmyadmin,mysql-error-1064,Php,Html,Mysql,Phpmyadmin,Mysql Error 1064,我有两个文件fourm.php和viewfourm.php <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASS"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="fourm"; // Table na
<?php
$host="mysql13.000webhost.com"; // Host name
$username="a2670376_Users"; // Mysql username
$password="PASS"; // Mysql password
$db_name="a2670376_Pass"; // Database name
$tbl_name="fourm"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// select record from mysql
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);
?>
<table>
<tr>
<td align="center"><strong>Post Number</strong></td>
<td align="center"><strong>UserName</strong></td>
<td align="center"><strong>Topic</strong></td>
<td align="center"><strong>Date</strong></td>
<td align="center"><strong>View</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><? echo $rows['fourmid']; ? > </td>
<td><? echo $rows['username']; ?> </td>
<td><? echo $rows['fourmname']; ? > </td>
<td><? echo $rows['date']; ?> </td>
<td><a href="fourm.php">back/a></td>
<?php
// close while loop
}
?>
</tr>
</table>
<?php
// close connection;
mysql_close();
?>
<hr width='67%' color='#29001F' size='3'/>
</center>
<?php
$host="mysql13.000webhost.com"; // Host name
$username="a2670376_Users"; // Mysql username
$password="PASS"; // Mysql password
$db_name="a2670376_Pass"; // Database name
$tbl_name="fourm"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// select record from mysql
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);
?>
<table>
<tr>
<td align="center"><strong>Post Number</strong></td>
<td align="center"><strong>UserName</strong></td>
<td align="center"><strong>Topic</strong></td>
<td align="center"><strong>Date</strong></td>
<td align="center"><strong>View</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><? echo $rows['fourmid']; ?> </td>
<td><? echo $rows['username']; ?> </td>
<td><? echo $rows['fourmname']; ? > </td>
<td><? echo $rows['date']; ?> </td>
<td><a href="viewfourm.php?id=<? echo $rows['fourmid']; ?>">View Topic</a></td>
<?php
// close while loop
}
?>
</tr>
</table>
<?php
// close connection;
mysql_close();
?>
<hr width='67%' color='#29001F' size='3'/>
</center>
<?php
$host="mysql13.000webhost.com"; // Host name
$username="a2670376_Users"; // Mysql username
$password="PASS"; // Mysql password
$db_name="a2670376_Pass"; // Database name
$tbl_name="fourm"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// select record from mysql
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);
?>
<table>
<tr>
<td align="center"><strong>Post Number</strong></td>
<td align="center"><strong>UserName</strong></td>
<td align="center"><strong>Topic</strong></td>
<td align="center"><strong>Date</strong></td>
<td align="center"><strong>View</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><? echo $rows['fourmid']; ? > </td>
<td><? echo $rows['username']; ?> </td>
<td><? echo $rows['fourmname']; ? > </td>
<td><? echo $rows['date']; ?> </td>
<td><a href="fourm.php">back/a></td>
<?php
// close while loop
}
?>
</tr>
</table>
<?php
// close connection;
mysql_close();
?>
<hr width='67%' color='#29001F' size='3'/>
</center>
现在在forum.php上，当我从MySql数据库中选择要查看的论坛时，它加载了我要修复的所有论坛，我知道它为什么这么做，原因是它的脚本与第一个相同，只是修改了一点，但我做了我能做的。我正在MySql数据库中选择forum s Throue fourmid标记，这就是>查看主题的内容，它应该使用viewfourm.php中选择的id加载论坛。修改您的sql查询$sql=SELECT*FROM$tbl\u name；像这样 $fourmid=$_POST['fourmid']//如果使用get方法传递，则使用$_get['fourmid']； $sql=从$tbl_名称中选择*其中fourmid='$fourmid' 还必须将fourmid从fourm.php传递到viewfourm.php
<?php
$host="mysql13.000webhost.com"; // Host name
$username="a2670376_Users"; // Mysql username
$password="PASS"; // Mysql password
$db_name="a2670376_Pass"; // Database name
$tbl_name="fourm"; // Table name
// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
// select record from mysql
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);
?>
<table>
<tr>
<td align="center"><strong>Post Number</strong></td>
<td align="center"><strong>UserName</strong></td>
<td align="center"><strong>Topic</strong></td>
<td align="center"><strong>Date</strong></td>
<td align="center"><strong>View</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><? echo $rows['fourmid']; ? > </td>
<td><? echo $rows['username']; ?> </td>
<td><? echo $rows['fourmname']; ? > </td>
<td><? echo $rows['date']; ?> </td>
<td><a href="fourm.php">back/a></td>
<?php
// close while loop
}
?>
</tr>
</table>
<?php
// close connection;
mysql_close();
?>
<hr width='67%' color='#29001F' size='3'/>
</center>
在form.php中，从
a href="viewfourm.php?id=<? echo $rows['fourmid']; ?>">View Topic</a>
试试看..sql vurnurable我知道我会在以后解决这个问题。它们不再得到维护，并且已经开始使用。看到了吗？相反，学习，并使用or-将帮助您决定哪一个。如果你选择PDO，.MySQLi我仍在学习MySql和php lol我将了解下一步，但对我来说，MySql更容易，也不使用空格对齐。警告：MySql_fetch_数组：提供的参数不是有效的MySql结果资源，位于/home/a2670376/public_html/fourms/viewfourm.php的第35行，我得到了这个，我对脚本做了这个操作//从MySql$fourmid选择记录=$_POST['fourmid']//如果使用get方法传递，则使用$_get['fourmid']$sql=从$tbl_名称中选择*其中fourmid='$fourmid'；在fourm.php中为每个主题创建一个链接，直到它不起作用为止我不理解你的意思或者它不起作用警告：mysql_fetch_数组：提供的参数不是第34行/home/a2670376/public_html/fourms/viewfourm.php中的有效mysql结果资源