Php mysql数据库按列搜索

我是mysql和php新手。我正在处理歌曲数据库。我有一个搜索脚本，它搜索数据库的所有列，并在表中显示结果。但我想让那个搜索脚本按所选列字段进行搜索。在搜索框下方，我想添加项目符号选项

（例如：按第1列、第2列、第3列、第4列进行搜索）

您可以看到下面的图片

歌曲数据库表

+----+--------+----------+-----+-------+
| id | title  | artist   | key | genre |
+----+--------+----------+-----+-------+
|  1 | xxxxx  | xxx xxxxx| xxx | xxxxx |    
|  2 | xxxxx  | xxx xxxxx| xxx | xxxxx |       
|  3 | xxxxx  | xxx xxxxx| xxx | xxxxx |       
|  4 | xxxxx  | xxx xxxxx| xxx | xxxxx |        
|  5 | xxxxx  | xxx xxxxx| xxx | xxxxx |        
+----+--------+----------+-----+-------+

搜索脚本：

 <?php 


    $host = "localhost";
    $user = "xxxxxxx";
    $password = "xxxxxxx";
    $database_name = "xxxxxx";
    $pdo = new PDO("mysql:host=$host;dbname=$database_name", $user, $password, array(
    PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION

    ));

$pdo->exec("set names utf8");
$search=$_POST['search'];
$query = $pdo->prepare("select * from table where title LIKE '%$search%' OR key LIKE '%$search%' OR genre LIKE '%$search%' OR artist LIKE '%$search%' LIMIT 0 , 100");
$query->bindValue(1, "%$search%", PDO::PARAM_STR);
$query->execute();

         if (!$query->rowCount() == 0) {

          $row_cnt = $result->num_rows;

    printf("<p class='notice'>Your search for <span class='blue'>“</span><span class='blue'>" . $result['search'] . "</span><span class='blue'>”</span> yielded %d results.\n</p>", $row_cnt);
                 echo "<table class='table'>";

                echo "<tr class='tablehead'>";

                    echo "<th>Title</th>";
                    echo "<th>Artist</th>";
                    echo "<th>Key</th>";
                    echo "<th>Genre</th>";
                    echo "</tr>";           
            while ($results = $query->fetch()) {
             echo "<tr>";

            echo "<td> <a href=publicsong.php?id=".$results['id'] . ">"  "</a> " . $results['title'] . " </td>";

                    echo "<td>" . $results['artist'] . "</td>";
                    echo "<td>" . $results['key'] . "</td>";
                    echo "<td>" . $results['genre'] . "</td>";

                echo "</tr>";

            }
                echo "</table>";        
        } else {
            echo 'Nothing found';
        }
?>

---

您应该获取单选按钮的值并进行适当的查询

$search=$_POST['search'];
$field=$_POST['radio_grp'];
switch($field)
{
case 'Title' : $filed='title' // or your column field
break;
//---similar cases
}
$query = $pdo->prepare("select * from table where $field LIKE '%$search%' LIMIT 0 , 100");

试试这个代码

将单选按钮的值设置为与列名相同

标题

艺术家

键

体裁

$search=$_POST['search']；
$search\u by=$\u POST['search\u by']；
$query=$pdo->prepare（“从表中选择*，其中$search_按“%$search%”限制为0，100”）；
嘿，罗希特。我更新了我的问题，请看一看。我不知道我哪里出错了。我看到一张空白页。Thq。
$search=$_POST['search'];
$field=$_POST['radio_grp'];
switch($field)
{
case 'Title' : $filed='title' // or your column field
break;
//---similar cases
}
$query = $pdo->prepare("select * from table where $field LIKE '%$search%' LIMIT 0 , 100");

<input type="radio" name="search_by" value="title">title<br>
<input type="radio" name="search_by" value="artist">artist<br>
<input type="radio" name="search_by" value="key">key<br>
<input type="radio" name="search_by" value="genre">genre<br>

$search=$_POST['search'];
$search_by=$_POST['search_by'];

$query = $pdo->prepare("select * from table where $search_by LIKE '%$search%' LIMIT 0 , 100");