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Php mySQL:如何加入只返回最新日志的用户日志?_Php_Mysql_Join - Fatal编程技术网

Php mySQL:如何加入只返回最新日志的用户日志?

Php mySQL:如何加入只返回最新日志的用户日志?,php,mysql,join,Php,Mysql,Join,嗨,伙计们,我有两张表,用户/日志之类的东西 tk_是用户的资产 tk_会话日志除非您需要其他信息,否则MAX应该帮助您 SELECT u.*, MAX(l.stamp_out) FROM user u INNER JOIN logs l ON l.user_id = u.id WHERE l.stamp_out = 0 GROUP BY u.id 如果您还需要更多,请看看这个问题:您的命名约定有点粗糙 SELECT assets.`ass_id`, sessions.`stamp_in`,

嗨,伙计们,我有两张表,用户/日志之类的东西

tk_是用户的资产
tk_会话日志除非您需要其他信息,否则MAX应该帮助您

SELECT u.*, MAX(l.stamp_out) FROM user u
INNER JOIN logs l ON l.user_id = u.id
WHERE l.stamp_out = 0
GROUP BY u.id

如果您还需要更多,请看看这个问题:

您的命名约定有点粗糙

SELECT assets.`ass_id`, sessions.`stamp_in`, sessions.`stamp_out`, sessions.`ass_id`
FROM tk_assets assets
LEFT JOIN tk_sessions sessions
ON assets.`ass_id` = sessions.`ass_id`
WHERE assets.`ass_id` = sessions.`ass_id`
GROUP BY sessions.`ass_id`
ORDER BY sessions.`stamp_in` DESC
SELECT assets.`ass_id`, sessions.`stamp_in`, sessions.`stamp_out`, sessions.`ass_id`
FROM tk_assets assets
LEFT JOIN tk_sessions sessions
ON assets.`ass_id` = sessions.`ass_id`
WHERE assets.`ass_id` = sessions.`ass_id`
GROUP BY sessions.`ass_id`
ORDER BY sessions.`stamp_in` DESC