Php 如果一个查询包含空结果，如何从多个查询打印？

我是PHP新手。我在浏览器上打印数据时遇到问题。我有五个问题。我的四个查询基于第一个查询的结果

第一次查询：

 $opinion_id = "SELECT `client_id` FROM `pacra_client_opinion_relations` WHERE `opinion_id` = 379";
$result = mysql_query($opinion_id) or die;
$row = mysql_fetch_assoc($result);
$client_id = $row['client_id'];

$q_opinion="SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT opinion_id FROM pacra_client_opinion_relations WHERE client_id = $client_id)
";

$q_opinion1 = "SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT client_id FROM og_ratings WHERE client_id = 379)";

$q_opinion2="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT `opinion_id` FROM `pacra_client_opinion_relations` WHERE `client_id` = $client_id) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT opinion_id FROM pacra_client_opinion_relations
    WHERE client_id = $client_id
  )";

$q_opinion3="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT client_id FROM og_ratings WHERE client_id = 379) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT client_id FROM og_ratings WHERE client_id = 379)
  )";

此查询获取

client\u id

，并在

client\u id

的基础上完成剩余的查询

查询2:

 $opinion_id = "SELECT `client_id` FROM `pacra_client_opinion_relations` WHERE `opinion_id` = 379";
$result = mysql_query($opinion_id) or die;
$row = mysql_fetch_assoc($result);
$client_id = $row['client_id'];

$q_opinion="SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT opinion_id FROM pacra_client_opinion_relations WHERE client_id = $client_id)
";

$q_opinion1 = "SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT client_id FROM og_ratings WHERE client_id = 379)";

$q_opinion2="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT `opinion_id` FROM `pacra_client_opinion_relations` WHERE `client_id` = $client_id) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT opinion_id FROM pacra_client_opinion_relations
    WHERE client_id = $client_id
  )";

$q_opinion3="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT client_id FROM og_ratings WHERE client_id = 379) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT client_id FROM og_ratings WHERE client_id = 379)
  )";

查询3:

 $opinion_id = "SELECT `client_id` FROM `pacra_client_opinion_relations` WHERE `opinion_id` = 379";
$result = mysql_query($opinion_id) or die;
$row = mysql_fetch_assoc($result);
$client_id = $row['client_id'];

$q_opinion="SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT opinion_id FROM pacra_client_opinion_relations WHERE client_id = $client_id)
";

$q_opinion1 = "SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT client_id FROM og_ratings WHERE client_id = 379)";

$q_opinion2="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT `opinion_id` FROM `pacra_client_opinion_relations` WHERE `client_id` = $client_id) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT opinion_id FROM pacra_client_opinion_relations
    WHERE client_id = $client_id
  )";

$q_opinion3="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT client_id FROM og_ratings WHERE client_id = 379) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT client_id FROM og_ratings WHERE client_id = 379)
  )";

查询4:

 $opinion_id = "SELECT `client_id` FROM `pacra_client_opinion_relations` WHERE `opinion_id` = 379";
$result = mysql_query($opinion_id) or die;
$row = mysql_fetch_assoc($result);
$client_id = $row['client_id'];

$q_opinion="SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT opinion_id FROM pacra_client_opinion_relations WHERE client_id = $client_id)
";

$q_opinion1 = "SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT client_id FROM og_ratings WHERE client_id = 379)";

$q_opinion2="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT `opinion_id` FROM `pacra_client_opinion_relations` WHERE `client_id` = $client_id) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT opinion_id FROM pacra_client_opinion_relations
    WHERE client_id = $client_id
  )";

$q_opinion3="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT client_id FROM og_ratings WHERE client_id = 379) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT client_id FROM og_ratings WHERE client_id = 379)
  )";

查询5:

 $opinion_id = "SELECT `client_id` FROM `pacra_client_opinion_relations` WHERE `opinion_id` = 379";
$result = mysql_query($opinion_id) or die;
$row = mysql_fetch_assoc($result);
$client_id = $row['client_id'];

$q_opinion="SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT opinion_id FROM pacra_client_opinion_relations WHERE client_id = $client_id)
";

$q_opinion1 = "SELECT r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM og_ratings r 
    inner join
(
  select max(notification_date) notification_date,
    client_id
  from og_ratings
  group by client_id
  ) r2
  on r.notification_date = r2.notification_date
  and r.client_id = r2.client_id
LEFT JOIN og_companies c
ON r.client_id = c.id
LEFT JOIN og_rating_types t
ON r.rating_type_id = t.id
LEFT JOIN og_actions a
ON r.pacra_action = a.id
LEFT JOIN og_outlooks o
ON r.pacra_outlook = o.id
LEFT JOIN og_lterms l
ON r.pacra_lterm = l.id
LEFT JOIN og_sterms s
ON r.pacra_sterm = s.id
LEFT JOIN pacra_client_opinion_relations pr
ON pr.opinion_id = c.id
LEFT JOIN pacra_clients pc
ON pc.id = pr.client_id
LEFT JOIN city
ON city.id = pc.head_office_id
WHERE r.client_id  IN (SELECT client_id FROM og_ratings WHERE client_id = 379)";

$q_opinion2="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT `opinion_id` FROM `pacra_client_opinion_relations` WHERE `client_id` = $client_id) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT opinion_id FROM pacra_client_opinion_relations
    WHERE client_id = $client_id
  )";

$q_opinion3="SELECT
   r.client_id,c.id,t.id,a.id,o.id,c.name as opinion, r.notification_date, t.title as ttitle,a.title as atitle,o.title as otitle, l.title as ltitle, s.title as stitle, pr.opinion_id, pc.id, pr.client_id as pr_client, pc.address, pc.liaison_one, city.id, pc.head_office_id, city.city, pc.title as cname
FROM
  og_ratings r 


  INNER JOIN (
    SELECT client_id, max(notification_date) notification_2nd_date
    FROM og_ratings
    WHERE client_id IN (SELECT client_id FROM og_ratings WHERE client_id = 379) AND
      (client_id, notification_date) NOT IN (
        SELECT client_id, max(notification_date)
        FROM og_ratings GROUP BY client_id
          ORDER BY  client_id DESC)
    GROUP BY client_id
      ORDER BY  client_id DESC
   ) r2
  ON r.notification_date = r2.notification_2nd_date
     AND r.client_id = r2.client_id
  LEFT JOIN og_companies c ON r.client_id = c.id
  LEFT JOIN og_rating_types t ON r.rating_type_id = t.id
  LEFT JOIN og_actions a ON r.pacra_action = a.id
  LEFT JOIN og_outlooks o ON r.pacra_outlook = o.id
  LEFT JOIN og_lterms l ON r.pacra_lterm = l.id
  LEFT JOIN og_sterms s ON r.pacra_sterm = s.id
  LEFT JOIN pacra_client_opinion_relations pr ON pr.opinion_id = c.id
  LEFT JOIN pacra_clients pc ON pc.id = pr.client_id
  LEFT JOIN city ON city.id = pc.head_office_id
WHERE
  r.client_id IN (
    SELECT client_id FROM og_ratings WHERE client_id = 379)
  )";

如果

query 1

query带来

client\u id

，则执行

query 2

和

query 4

，但如果没有

client\u id

则执行

query 3

和

query 5

if ($client_id == NULL)
{
    $query = $q_opinion1;
    $query1 = $q_opinion3;
    }
    else{
$query = $q_opinion;
$query1 = $q_opinion2;
    }
  $result1 = mysql_query($query) or die;
  $result2 = mysql_query($query1) or die;

剩下的PHP代码是

$opinion = array();

while($row1 = mysql_fetch_assoc($result1))
{        
    $opinion[]= $row1['opinion'];
    $action[]= $row1['atitle'];
    $long_term[]= $row1['ltitle'];
    $outlook[]= $row1['otitle'];
    $rating_type[]= $row1['ttitle'];
    $short_term[]= $row1['stitle'];


}
while($row2 = mysql_fetch_assoc($result2))
{
    $p_long_term[]= $row2['ltitle'];
    $p_short_term[]= $row2['stitle'];
}
?>

我的HTML代码是

<table width="657">
        <tr>
            <td width="225"> <strong>Opinion</strong></td>
            <td width="62"> <strong>Action</strong></td>
            <td colspan="4"><strong>Ratings</strong></td>
            <td width="54"><strong>Outlook</strong></td>
            <td width="67"><strong>Rating Type</strong></td>
        </tr>
        <tr>
          <td width="225">&nbsp;</td>
          <td width="62">&nbsp;</td>
          <td colspan="2"><b>Long Term</b></td>
          <td colspan="2"><b>Short Term</b></td>
          <td width="54">&nbsp;</td>
          <td width="67">&nbsp;</td>
        </tr>
        <tr>
          <td width="225">&nbsp;</td>
          <td width="62">&nbsp;</td>
          <td width="52"><b>Current</b></td>
          <td width="45"><b>Previous</b></td>
          <td width="49"><b>Current</b></td>
          <td width="51"><b>Previous</b></td>
          <td width="54">&nbsp;</td>
          <td width="67">&nbsp;</td>
        </tr>
        <?php
        for ($i=0; $i<count($opinion); $i++) {
    //if ($opinion[$i] == "")continue;
        ?>


    <tr>
           <td><?php echo $opinion[$i]?></td>
          <td><?php echo $action[$i] ?></td>
          <td><?php echo $long_term[$i] ?></td>
          <td><?php echo $p_long_term[$i]?></td>
          <td><?php echo $short_term[$i] ?></td>
          <td><?php echo $p_short_term[$i] ?></td>
          <td><?php echo $outlook[$i] ?></td>
          <td><?php echo $rating_type[$i] ?></td>
        </tr>

        <?php
        }
?>
 </table>

意见
行动
评级
展望
评级类型
长期
短期的
现在的
以前的
现在的
以前的

现在的问题是

---

有时我的

查询5

包含空结果。由于这个问题，

查询3

的数据没有打印出来。我希望，如果我的任何查询包含空结果，我的其余数据将打印在我的页面上。

您似乎在意见数组上循环，并使用索引选择$p_long_term[]和$p_short_term[]数组中的相应值。如果查询5失败，这些数组将为空

<tr>
       <td><?php echo $opinion[$i]?></td>
      <td><?php echo $action[$i] ?></td>
      <td><?php echo $long_term[$i] ?></td>
      <td><?php echo $p_long_term[$i]?></td>**
      <td><?php echo $short_term[$i] ?></td>
      <td><?php echo $p_short_term[$i] ?></td>
      <td><?php echo $outlook[$i] ?></td>
      <td><?php echo $rating_type[$i] ?></td>
    </tr>

**

在echo之前检查密钥是否存在

<td><?php if(array_key_exists ($i, $p_long_term))echo $p_long_term[$i]?></td>
<td><?php if(array_key_exists ($i, $p_short_term))echo $p_short_term[$i] ?></td>

---

问题在于循环期间的逻辑。您正在回显query5数组中不存在的内容。您可以尝试先检查元素是否存在，然后再返回到out stream

for ($i=0; $i<count($opinion); $i++) {
    echo '<tr>';
    echo isset($opinion[$i])?  '<td>'. $opinion[$i] .'</td>' : '';
    echo isset($action[$i])?  '<td>'. $action[$i] .'</td>' : '';
    echo isset($long_term[$i])?  '<td>'. $long_term[$i] .'</td>' : '';
    echo isset($p_long_term[$i])?  '<td>'. $p_long_term[$i] .'</td>' : '';
    echo isset($short_term[$i])?  '<td>'. $short_term[$i] .'</td>' : '';
    echo isset($p_short_term[$i])?  '<td>'. $p_short_term[$i] .'</td>' : '';
    echo isset($outlook[$i])?  '<td>'. $outlook[$i] .'</td>' : '';
    echo isset($rating_type[$i])?  '<td>'. $rating_type[$i] .'</td>' : '';
    echo '</tr>';
}

对于（$i=0；$i使用此

$max = max(count($opinion),count($p_long_term));
for ($i=0; $i<$max; $i++) {
    echo '<tr>';
    echo isset($opinion[$i])?  '<td>'. $opinion[$i] .'</td>' : '';
    echo isset($action[$i])?  '<td>'. $action[$i] .'</td>' : '';
    echo isset($long_term[$i])?  '<td>'. $long_term[$i] .'</td>' : '';
    echo isset($p_long_term[$i])?  '<td>'. $p_long_term[$i] .'</td>' : '';
    echo isset($short_term[$i])?  '<td>'. $short_term[$i] .'</td>' : '';
    echo isset($p_short_term[$i])?  '<td>'. $p_short_term[$i] .'</td>' : '';
    echo isset($outlook[$i])?  '<td>'. $outlook[$i] .'</td>' : '';
    echo isset($rating_type[$i])?  '<td>'. $rating_type[$i] .'</td>' : '';
    echo '</tr>';
}

$max=max（计数（$opinion），计数（$p_long_term））；
对于（$i=0；$i不使用MySQL_*函数此扩展在PHP5.5.0中被弃用，并在PHP7.0.0中被删除。相反，应该使用or扩展。@sunny我可能错了，但很难猜测您真正的问题是什么？请删除不相关的代码，只关注问题。@sitilge所有代码都是相关的。我的问题是我显示两个查询的组合中的数据。有时我显示查询2和查询4的组合中的数据，有时我显示查询3和查询5的组合中的数据。如果我的查询5有空记录，则它不会显示查询3的结果。我发现如果查询5为空，则它将能够显示查询的结果查询3@sunny您是否尝试过
if（empty（$result5））{while（$row3=mysql_fetch_assoc（$result3））{print_r（$row3}}}
？@sitilge如果我创建了另一个循环，那么我如何使用HTML
显示我的记录，而（$row2=mysql_fetch_assoc（$result2））{$p_long_term[]=$row2['ltitle']；$p_short.=$row2['stitle]}
我正在使用此循环并获取记录
@sitilge it show
已弃用：mysql\u connect（）
error@sunny你使用的是不推荐使用的方法。我想知道为什么这些充满错误信息的噩梦网站仍然会从谷歌搜索中弹出…不要使用mysql，最好切换到PDO或其他抽象层，如DoctrineTry，以便尝试对echo$p_long_term和$p_short_term进行评论，并检查问题是否仍然存在。然后反向查找错误这与@faiz的答案相同，只是推导出了
$max