Php 获取数组中的重复值,同时忽略值前面的某些值和数字
我试图找出数组中除了分析证书和bellow之外的相同值是否是我的数组Php 获取数组中的重复值,同时忽略值前面的某些值和数字,php,arrays,Php,Arrays,我试图找出数组中除了分析证书和bellow之外的相同值是否是我的数组 [0] => 1009 [1] => 1033 [2] => 2052 [3] => ANNEX 4E [4] => Bill of Lading [5] => CERTIFICATE OF ANALYSIS 123456 [6] => CERTIFICATE OF ANALYSIS 000999 [7] => CERTIFICATE OF ORIGIN 123456 [8] =
[0] => 1009
[1] => 1033
[2] => 2052
[3] => ANNEX 4E
[4] => Bill of Lading
[5] => CERTIFICATE OF ANALYSIS 123456
[6] => CERTIFICATE OF ANALYSIS 000999
[7] => CERTIFICATE OF ORIGIN 123456
[8] => CERTIFICATE OF ORIGIN 789934
[9] => DHL - 1387563870
[10] => DHL - 5130431633
所以在检查之后,我期待下面的结果
[1] => CERTIFICATE OF ORIGIN 123456
[2] => CERTIFICATE OF ORIGIN 789934
[3] => DHL - 1387563870
[4] => DHL - 5130431633
由于原产地证书出现了两次,DHL出现了两次,但分析证书除外
我尝试使用下面的代码
function array_not_unique( $a = array() )
{
return array_diff_key( $a , array_unique( $a ) );
}
但是由于名字前面有一些数字,所以不能把它弄出来。这里是否需要使用正则表达式以及如何使用?您可以首先使用正则表达式提取“键”信息,然后将值按键存储在关联数组中。最后,从键具有多个关联值的关联数组中获取值:
function array_not_unique( $a = [] ) {
$byKey = [];
foreach($a as $val) {
$key = preg_replace("/[^a-z]+$/i", "", $val);
if ($key && $key != "CERTIFICATE OF ANALYSIS") $byKey[$key][] = $val;
}
$result = [];
foreach($byKey as $arr) {
if (count($arr) > 1) $result = array_merge($result, $arr);
}
return $result;
}
这是非常好的回答,先生!