Php 向表中添加计数器

Php 向表中添加计数器,php,Php,我正试图在下面的代码中将计数器添加到表中。但我不可能成功。能帮我一点忙吗?谢谢大概是这样的: $counter = 0; $counter++; if($counter % 33 == 0) <!DOCTYPE html> <html> <head> <title></title> <link rel="stylesheet" type="text/css" href="etc/sumain.css" />

我正试图在下面的代码中将计数器添加到表中。但我不可能成功。能帮我一点忙吗?谢谢大概是这样的:

$counter = 0;
$counter++;
if($counter % 33 == 0)
<!DOCTYPE html>
<html>

<head>
    <title></title>
    <link rel="stylesheet" type="text/css" href="etc/sumain.css" />
</head>

<body>

<?php 

include ("confige.php");

$query = 'select * from employees'; 
$result = mysqli_query($link, $query); 
if (!$result) { 
    $message = 'ERROR:' . mysqli_error($link); 
    return $message; 
} else { 
    $i = 0; 
    echo '<form name="select" action="" method="GET">';
    echo '<select name="mySelect" id="mySelect"  onchange="this.form.submit()">'; 
    while ($i < mysqli_field_count($link)) { 
        $meta =  
            mysqli_fetch_field_direct($result, $i); 
        echo '<option>' . $meta->name . '</option>'; 
        $i = $i + 1; 
    } 
    echo '</select>';
    echo '</form>';
}

if(isset($_GET['mySelect'])) {
    $myselect = $_GET['mySelect']; 

    $sql = "SELECT `$myselect` as mySelect FROM employees";  // add column alias
    $result = mysqli_query($link, $sql);   

    if ($result->num_rows > 0) {

        // output data of each row
        $table_row_counter = 0;
        echo '<table class="tbresult">';

        while($row = $result->fetch_assoc()) 
        {
            $table_row_counter++;
            if ($table_row_counter % 33 == 0) {
                echo '</table>';
                echo '<table class="tbresult">';
            }
            echo "<tr><td>" . $row["mySelect"] . "</td></tr>";

        }
    }
} 


mysqli_close($link);

?>

</body>

</html>
因此,当添加计数器时,表将在页面右侧的%33之后继续,并且它将像那样继续,而不是沿着页面向下

<!DOCTYPE html>
<html>

<head>
    <title></title>
<link rel="stylesheet" type="text/css" href="etc/sumain.css" />
    </head>

    <body>

<table class="tbresult">

<?php 

include ("confige.php");

$query = 'select * from employees'; 
$result = mysqli_query($link, $query); 
if (!$result) { 
    $message = 'ERROR:' . mysqli_error($link); 
    return $message; 
} else { 
    $i = 0; 
    echo '<form name="select" action="" method="GET">';
     echo '<select name="mySelect" id="mySelect"  onchange="this.form.submit()">'; 
    while ($i < mysqli_field_count($link)) { 
        $meta =  
        mysqli_fetch_field_direct($result, $i); 
        echo '<option>' . $meta->name . '</option>'; 
        $i = $i + 1; 
    } 
echo '</select>';
echo '</form>';
} 

if(isset($_GET['mySelect'])) {
$myselect = $_GET['mySelect']; 

$sql = "SELECT `$myselect` as mySelect FROM employees";  // add column alias
$result = mysqli_query($link, $sql);   

  if ($result->num_rows > 0) {

   // output data of each row
   while($row = $result->fetch_assoc()) 
   {
        echo "<tr><td>" . $row["mySelect"] . "</td></tr>";

   }

      echo "</table>";


}

} 


mysqli_close($link);

?>

</body>

</html>

首先,表格中没有HTML表单,这是无效的,AFIK,在不同的浏览器中可能会给您带来很多麻烦

只需打开该表一次,然后创建一个计数器=0,并在每个while循环上向其添加1。然后检查,如果它除以33,则关闭表并打开一个新表。循环结束后,关闭最后一个表

并排对齐可以用CSS完成,类似于
.tbresult{float:left;width:200px;}

大概是这样的:

$counter = 0;
$counter++;
if($counter % 33 == 0)
<!DOCTYPE html>
<html>

<head>
    <title></title>
    <link rel="stylesheet" type="text/css" href="etc/sumain.css" />
</head>

<body>

<?php 

include ("confige.php");

$query = 'select * from employees'; 
$result = mysqli_query($link, $query); 
if (!$result) { 
    $message = 'ERROR:' . mysqli_error($link); 
    return $message; 
} else { 
    $i = 0; 
    echo '<form name="select" action="" method="GET">';
    echo '<select name="mySelect" id="mySelect"  onchange="this.form.submit()">'; 
    while ($i < mysqli_field_count($link)) { 
        $meta =  
            mysqli_fetch_field_direct($result, $i); 
        echo '<option>' . $meta->name . '</option>'; 
        $i = $i + 1; 
    } 
    echo '</select>';
    echo '</form>';
}

if(isset($_GET['mySelect'])) {
    $myselect = $_GET['mySelect']; 

    $sql = "SELECT `$myselect` as mySelect FROM employees";  // add column alias
    $result = mysqli_query($link, $sql);   

    if ($result->num_rows > 0) {

        // output data of each row
        $table_row_counter = 0;
        echo '<table class="tbresult">';

        while($row = $result->fetch_assoc()) 
        {
            $table_row_counter++;
            if ($table_row_counter % 33 == 0) {
                echo '</table>';
                echo '<table class="tbresult">';
            }
            echo "<tr><td>" . $row["mySelect"] . "</td></tr>";

        }
    }
} 


mysqli_close($link);

?>

</body>

</html>


看起来您正在将get请求中的值直接插入mysql查询。这不是一种安全威胁吗?可能是。目前它只在本地主机上使用。我没有得到你想要的。你想把桌子分成不超过33行的几行吗?是的,这就是我想做的。这张桌子从这一页一直下到底部。我希望它在页面右侧并排排列。非常感谢!这个很好用!。我也会检查CSS版本。再次感谢你。