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我有一些php代码,在代码的标题中,我想给出我的ionic应用程序页面的链接_Php_Html_Ionic Framework - Fatal编程技术网

我有一些php代码,在代码的标题中,我想给出我的ionic应用程序页面的链接

我有一些php代码,在代码的标题中,我想给出我的ionic应用程序页面的链接,php,html,ionic-framework,Php,Html,Ionic Framework,page.php: if($order_status != 'Success'){ $date = date('d-M-Y h:i:sa'); $new = mysqli_query($conn, "UPDATE `event_reg` SET payment_date = '$date', status_text = '$order_status;', tid = '$transaction_id', order_id = '$order_id' WHERE reg_id =

page.php

if($order_status != 'Success'){ 
    $date = date('d-M-Y h:i:sa');
    $new = mysqli_query($conn, "UPDATE `event_reg` SET payment_date = '$date', status_text = '$order_status;', tid = '$transaction_id', order_id = '$order_id' WHERE reg_id = '$tidd'");

    header("location:canceled.php?reg_id=$tidd");
}
页面的页眉位置是
cancelled.php
,但我不想这样。我想在我的ionic应用程序页面中重定向它,看看它是如何实现的。我的php页面位于服务器上,项目位于
localhost

而不是

header("location:canceled.php?reg_id=$tidd");
使用


我的应用程序在localserver上
header("Location: https://YourIonicAppUrl/");