Php 如何仅在表单提交后显示Div标记?
如何仅在表单提交后显示div标记 通过使用js或php 我想在提交表格后显示Php 如何仅在表单提交后显示Div标记?,php,html,forms,Php,Html,Forms,如何仅在表单提交后显示div标记 通过使用js或php 我想在提交表格后显示 Div标签代码: <script type="javascript"> function onSubmit(){ document.getElementById('submitButton').style.display = "none"; document.getElementById('progressBar').style.display = "block"; } </scrip
Div标签代码:
<script type="javascript">
function onSubmit(){
document.getElementById('submitButton').style.display = "none";
document.getElementById('progressBar').style.display = "block";
}
</script>
<video id='video01' width='160' height='90' data-autoresize='fit' data-volume=".5" >
<source type="video/mp4" src="<?php $data = json_decode($getGP, true); echo $data[1]['file'];?>" />
<source type="video/mp4" src="<?php $data = json_decode($getGP, true); echo $data[0]['file'];?>" data-quality="hd"/>
</video>
<div id="submitButton">
<button class="button button1" ><a class='afterglow' id="mytrigger" href="#video01">Play Now</a></button>
</div>
函数onSubmit(){
document.getElementById('submitButton').style.display=“无”;
document.getElementById('progressBar').style.display=“block”;
}
如果您想要一个JavaScript
实现,您可以创建一个CSS
类规则来最初隐藏
,然后在onSubmit()
函数回调中添加一个CSS类,将显示从display:none代码>至<代码>显示:块代码>符合以下内容的内容:
函数onSubmit(){
var element=document.getElementById('submitButton')
element.className+=“show ele”;
}
。隐藏元素{
显示:无;
}
.表演{
显示:块;
}
提交按钮Div
所以只有当设置为($\u POST['submit'])时才显示它代码>
<form action="" method="POST" onSubmit="return onSubmit()"return false;>
<input type="text" size="80" name="url" value="https://photos.google.com/share/AF1QipMTEPAiVF8t0YqLukflnOSQjwfd8ARIoT2h37AXvYO1uaWodbeiFoBUDuD_19tEbg/photo/AF1QipPA2Bq0JlAR9LoGD3mogsxSb9OZWEG4XqBDD4Rv?key=cjhUT0xrZjM5NGN2SVRLOVptZU5SMUlKV0lQYWpB"/>
<input type="submit" value="Load Now" name="submit" />
</form>
<?php
if( $_SERVER['REQUEST_METHOD']=='POST' ){
?>
<div id="submitButton">
<button class="button button1" ><a class='afterglow' id="mytrigger" href="#video01">Play Now</a></button>
</div>
<?php
}//close if
?>