Php SQL与其他表联接并添加案例

下面的查询告诉我在同一天有多少销售额。 还有多少新用户，和信用

这是我的工作查询，它工作得很好！：

SELECT Substring(purchase.`date`,1,10)                       AS `DayDate`, 
                   Sum(Cast(Substring(purchase.`item`, 12) AS UNSIGNED))     AS `Credit`,
                   Count(1)                                                  AS `Sales`,
                   (SELECT Count(*) FROM enswitch_mobile_users WHERE Date(purchase.`date`) = Substring(enswitch_mobile_users.`creation_date`,1,10))  AS `New_users`
                        FROM   (SELECT item, date 
                                    FROM enswitch_new_iphone_purchases WHERE `status`=1
                                    UNION 
                                    SELECT item, date 
                                    FROM enswitch_new_android_purchases WHERE `status`=1) AS `purchase` 
                        WHERE purchase.`date` >= :from_date AND purchase.`date` <= :to_date
                GROUP  BY `DayDate` 
                ORDER  BY `DayDate` DESC

我在这里搜索3张表。 enswitch_new_android_购买enswitch_new_iphone_购买 它们都有item、user\u id、status和date列。 一个条目的示例：

日期：2012-08-01 16:24:30 项目：xsalnx.sip.70 用户识别码：1337 现状：1

还从enswitch_mobile_usersid、创建日期、移动id等提取移动_用户数量。。。并以特定的日期分组

我试图做的是添加一个测试，如果购买的用户或新用户是测试人员。如果是这样，我想忽略查询中的这些数据

我将测试人员保存在一张名为： enswitch_测试_设备id、名称、移动_id

我可以将数据加入到enswitch_mobile_users mobile_id列中

到目前为止，我试图使它工作，但没有运气。。

---

如何执行此查询？

请尝试下面的操作-在获取用户时添加一个子句-获取除test之外的所有用户。现在，一个示例数据和结构表将有所帮助。我认为您可以重新编写查询

SELECT Substring(purchase.`date`,1,10)                       AS `DayDate`, 
                   Sum(Cast(Substring(purchase.`item`, 12) AS UNSIGNED))     AS `Credit`,
                   Count(1)                                                  AS `Sales`,
                   (
                        SELECT Count(*) 
                        FROM enswitch_mobile_users 
                        WHERE 
                            Date(purchase.`date`) = Substring(enswitch_mobile_users.`creation_date`,1,10) 
                            AND enswitch_mobile_users.mobile_id NOT IN ( select mobile_id from enswitch_testing_devices WHERE 'is tester')
                    )  AS `New_users`
                        FROM   (SELECT item, date 
                                    FROM enswitch_new_iphone_purchases WHERE `status`=1
                                    UNION 
                                    SELECT item, date 
                                    FROM enswitch_new_android_purchases WHERE `status`=1) AS `purchase` 
                        WHERE purchase.`date` >= :from_date AND purchase.`date` <= :to_date
                GROUP  BY `DayDate` 
                ORDER  BY `DayDate` DESC

---

我设法解决了这个问题

如果有人想知道的话

function search_daily_sales($from_date, $to_date ,$show_testers)
{
        // If not showing the testers
    if ($show_testers === false) 
    {
        $sql = "SELECT Substring(purchase.`date`,1,10)                            AS `DayDate`,
                        Sum(CASE WHEN td.mobile_id IS NULL 
                            THEN Cast(Substring(purchase.`item`, 12) AS UNSIGNED) 
                            ELSE '0' END)                                         AS `Credit`,
                        Sum(CASE WHEN td.mobile_id IS NULL THEN '1' ELSE '0' END) AS `Sales`,
                        (SELECT Count(*) FROM enswitch_mobile_users 
                            WHERE 
                                Date(purchase.`date`) = Substring(enswitch_mobile_users.`creation_date`,1,10)
                            AND enswitch_mobile_users.`mobile_id` NOT IN (SELECT mobile_id FROM enswitch_testing_devices))  AS `New_users`,
                    MIN(CASE WHEN td.mobile_id IS NULL THEN '0' ELSE '1' END)    AS `tester`

                    FROM   (SELECT item, date, user_id
                                FROM enswitch_new_iphone_purchases WHERE `status`=1
                                UNION 
                                SELECT item, date, user_id
                                FROM enswitch_new_android_purchases WHERE `status`=1) AS `purchase` 

                    LEFT JOIN enswitch_mobile_users mu ON mu.id = purchase.user_id
                    LEFT JOIN enswitch_testing_devices td ON td.mobile_id = mu.mobile_id

                    WHERE purchase.`date` >= :from_date AND purchase.`date` <= :to_date
            GROUP  BY `DayDate` 
            ORDER  BY `DayDate` DESC";
    }
    else 
    {
        $sql = "SELECT Substring(purchase.`date`,1,10)                       AS `DayDate`, 
               Sum(Cast(Substring(purchase.`item`, 12) AS UNSIGNED))     AS `Credit`,
               Count(1)                                                  AS `Sales`,
               (SELECT Count(*) FROM enswitch_mobile_users WHERE Date(purchase.`date`) = Substring(enswitch_mobile_users.`creation_date`,1,10))  AS `New_users`
                    FROM   (SELECT item, date 
                                FROM enswitch_new_iphone_purchases WHERE `status`=1
                                UNION 
                                SELECT item, date 
                                FROM enswitch_new_android_purchases WHERE `status`=1) AS `purchase` 
                    WHERE purchase.`date` >= :from_date AND purchase.`date` <= :to_date
            GROUP  BY `DayDate` 
            ORDER  BY `DayDate` DESC";
    }

    $result = DB::query(Database::SELECT, $sql)->bind(':from_date', $from_date)->
                                                bind(':to_date', $to_date)->execute();

return $result;
}

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谢谢，但这不起作用，它仍然会将测试人员的销售额返还给我：/