在PHP中，如何在heredoc（此处为文档）中折叠换行符？

出于CLI目的，我希望在

herdoc

（此处为文档）中部分折叠（忽略换行）

目前，我在要折叠的行的末尾使用

%%

，然后使用

str\u replace（“%%\n”，“'.$string”）替换它们。但是我觉得不太舒服

有没有逃生绳或更聪明的方法

例如：

<?php

$string=<<<EOL
This is a single long line, and it has to be
in one line, though the SideCI thing (as a 
coding regulation) I have to line break.
But this line stays short.
And this line too.
And the backslash such as \
won't work. Nor /
won't work.
My alternative way is to use %%
strings and replace them later.

EOL;

$string .= 'And I don\'t want to do this ';
$string .= 'to merge strings.';

echo str_replace("%%\n",'', $string);

有什么想法吗


当前结论（2018/01/17）
禁用换行符作为默认行为，并改用
BR
标记换行。

1.将
PHP\u EOL
（换行符）替换为“”（空白）。

2.将
BR
标记替换为
PHP\u EOL


示例代码：

<?php

$string=<<<EOL
This is a single long line, and it has to be
in one line, though the SideCI thing (as a 
coding regulation) I have to line break.<br>
But this line stays short.<br>
And this line too.<br>
My post alternative way was to use %%
chars and replace them later.<br>

EOL;

$string = str_replace(PHP_EOL,'', $string);
$string = str_ireplace(["<br />","<br>","<br/>"], PHP_EOL, $string);

echo $string;

就个人而言，我会使用类似于
{nbr}
的东西，因为
%%
似乎太泛化了，其中
{nbr}
是“不间断的”，而
{…}
在模板中很常见，这只是一种观点

但我也会使用regx而不是str_替换

preg_replace('/{nbr}[\r\n]+/', '', $str);

通过这种方式，它可以匹配
\r
、
\r\n
、
\n
甚至
\n\n
或旧的Mac、Windows、Linux和多行终端

您可以看到
您可以求助于破坏HTML标准，即使用

标记来表示何时需要换行。这会让习惯HTML的人感觉更直观

$string=<<<EOL
This is a single long line, and it has to be
in one line, though the SideCI thing (as a
coding regulation) I have to line break.
But this line stays short.
And this line too.
And the backslash such as \<br>
won't work. Nor /<br>
won't work.<br>
My alternative way is to use %%<br>
strings and replace them later.

EOL;

$string = str_replace(PHP_EOL,'', $string);
$string = str_ireplace(["<br />","<br>","<br/>"], PHP_EOL, $string);
echo $string;

$string=
这会让习惯HTML的人感觉更直观…
我明白了，首先删除所有换行符，然后将BR标记替换为换行符。这是一个好主意，而且很直观！所以没有转义码可以取消换行吗？
因为%%看起来太通用了
确实如此。但以前它是
%BR%
。但有时有人更改了孔规格，认为是因为他/她懒惰打字。这就是为什么我会有这种不舒服的感觉_(
$string=<<<EOL
This is a single long line, and it has to be
in one line, though the SideCI thing (as a
coding regulation) I have to line break.
But this line stays short.
And this line too.
And the backslash such as \<br>
won't work. Nor /<br>
won't work.<br>
My alternative way is to use %%<br>
strings and replace them later.

EOL;

$string = str_replace(PHP_EOL,'', $string);
$string = str_ireplace(["<br />","<br>","<br/>"], PHP_EOL, $string);
echo $string;