Php Laravel插入和检索关系
我正在做一个基于Laravel3的项目,我想看看是否可以缩短处理关系的代码(做以下事情的更好方法) 用户控制器 创建用户功能Php Laravel插入和检索关系,php,orm,laravel,relationship,eloquent,Php,Orm,Laravel,Relationship,Eloquent,我正在做一个基于Laravel3的项目,我想看看是否可以缩短处理关系的代码(做以下事情的更好方法) 用户控制器 创建用户功能 .... $table->integer('organization_id')->unsigned()->nullable(); $table->foreign('organization_id')->references('id')->on('organizations'); $table->integer('school_i
....
$table->integer('organization_id')->unsigned()->nullable();
$table->foreign('organization_id')->references('id')->on('organizations');
$table->integer('school_id')->unsigned()->nullable();
$table->foreign('school_id')->references('id')->on('schools');
....
....
$table->increments('id');
$table->string('name');
$table->string('slug');
$table->integer('count')->default(1)->unsigned();
....
创建或检索学校/组织id
模型 用户模型
class User extends Eloquent {
public function organization()
{
return $this->belongs_to('Organization');
}
public function school()
{
return $this->belongs_to('School');
}
}
class Organization extends Eloquent {
public function user()
{
return $this->has_many('User');
}
}
组织/学校模式
class User extends Eloquent {
public function organization()
{
return $this->belongs_to('Organization');
}
public function school()
{
return $this->belongs_to('School');
}
}
class Organization extends Eloquent {
public function user()
{
return $this->has_many('User');
}
}
迁移 用户迁移
....
$table->integer('organization_id')->unsigned()->nullable();
$table->foreign('organization_id')->references('id')->on('organizations');
$table->integer('school_id')->unsigned()->nullable();
$table->foreign('school_id')->references('id')->on('schools');
....
....
$table->increments('id');
$table->string('name');
$table->string('slug');
$table->integer('count')->default(1)->unsigned();
....
组织/学校迁移
....
$table->integer('organization_id')->unsigned()->nullable();
$table->foreign('organization_id')->references('id')->on('organizations');
$table->integer('school_id')->unsigned()->nullable();
$table->foreign('school_id')->references('id')->on('schools');
....
....
$table->increments('id');
$table->string('name');
$table->string('slug');
$table->integer('count')->default(1)->unsigned();
....
现在,我的问题是:
School::find($schoolId)->get()
User::find(1)->school()
操作不会检索学校的任何数据,仅:
[base:protected] => User Object
(
[attributes] => Array
(
[id] => 1
[nickname] => w0rldart
....
[organization_id] =>
[school_id] => 1
...
)
[relationships] => Array
(
)
[exists] => 1
[includes] => Array
(
)
)
[model] => School Object
(
[attributes] => Array
(
)
[original] => Array
(
)
[relationships] => Array
(
)
[exists] =>
[includes] => Array
(
)
)
有没有比上面使用的更好的方法来生成用户->学校/组织
关系?如果是,怎么做
雄辩应该能够自动处理,请参见此处:
检索用户学校/组织名称的更好方法是:School::find($schoolId)->get()
如果您的意思是无法检索关系信息:具有\u name
并且属于\u
返回一个易懂的表达式,您仍然需要对它们调用get()
,以检索所需的对象或集合
我处理这个问题的方法是为关系添加一个参数,以确定该方法是否应返回表达式或结果:
$table->increments('id');
$table->string('name');
$table->string('slug');
$table->integer('count')->default(1)->unsigned();
$table->unique('name');
...
class User extends Eloquent
{
/**
* Return an Elloquent Expression or a collection (or object)
* Defaults to return a collection
*/
public function organization ($as_expression=FALSE) {
$related = $this->belongs_to('Organization');
return $as_expression ? $related : $related->get();
}
public function school ($as_expression=FALSE) {
$related = $this->belongs_to('School');
return $as_expression ? $related : $related->get();
}
...
public function create ($user_data=array()) {
$newUser = new User;
$activity = @$user_data['organization'] ?
'organization' : (@$user_data['school'] ? 'school' : '');
switch ($activity) {
case 'organization':
case 'school':
/**
* Call the corresponding method, return as Eloquent Expression
* Use a string to be verbose, TRUE does fine if wanted
*/
$new_user->{$activity}('as_expression')->save(array( 'name' => $user_data[$activity]));
break;
default:
break;
}
return $new_user;
}
}
...
class Organization extends Eloquent
{
public function user ($as_expression=FALSE) {
$related = $this->has_many('User');
return $as_expression ? $related : $related->get();
}
}
问题是,目前还没有自动完成功能,因此任何输入都是新输入,没有组织的现有ID唯一名称。因此,组织也必须插入我,并与用户相关有趣,我会尽快尝试,并让您知道