php无法识别JSON post消息
我正在努力通过XMLhttp post请求发送JSON数据。 数据如下:php无法识别JSON post消息,php,json,Php,Json,我正在努力通过XMLhttp post请求发送JSON数据。 数据如下: "{"reqData":{"reqType":"post","reqName":"getCurrTemp","reqPayload":""}}" JS代码是: var reqData = { reqType : "post", //isDateRequested : 1, reqName : "getCurrTemp", reqP
"{"reqData":{"reqType":"post","reqName":"getCurrTemp","reqPayload":""}}"
JS代码是:
var reqData = {
reqType : "post", //isDateRequested : 1,
reqName : "getCurrTemp",
reqPayload : ""
};
var dataToSend = {'reqData' : reqData };
var jData = JSON.stringify(dataToSend);
alert(jData);
var oReq = new XMLHttpRequest();
oReq.onload = function() {
data = JSON.parse(this.responseText);
};
oReq.open("POST", "handleRequests.php", true);
oReq.send(jData);
我在php端有问题,看起来服务器不识别JSON,甚至消息丢失
我用wireshark嗅探流量:
POST /autHouse/handleRequests.php HTTP/1.1
Host: 192.168.0.12
Connection: keep-alive
Content-Length: 70
Origin: http://192.168.0.12
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.111 Safari/537.36
Content-Type: text/plain;charset=UTF-8
Accept: */*
Referer: http://192.168.0.12/autHouse/ah.html
Accept-Encoding: gzip, deflate
Accept-Language: pl-PL,pl;q=0.8,en-US;q=0.6,en;q=0.4
{"reqData":{"reqType":"post","reqName":"getCurrTemp","reqPayload":""}}HTTP/1.1 200 OK
Date: Tue, 19 Jan 2016 10:53:22 GMT
Server: Apache/2.2.22 (Debian)
X-Powered-By: PHP/5.4.45-0+deb7u2
Content-Length: 84
Keep-Alive: timeout=5, max=99
Connection: Keep-Alive
Content-Type: text/html
string(70) "{"reqData":{"reqType":"post","reqName":"getCurrTemp","reqPayload":""}}"
以下是php代码:
$body = file_get_contents('php://input');
error_log(var_dump($body));
$reqData= json_decode($_POST['reqData'], true);
$reqType = $reqData["reqType"];
$reqName = $reqData["reqName"];
和实时php错误日志:
[Tue Jan 19 11:54:23 2016] [error] [client 192.168.0.121] , referer: http://192.168.0.12/autHouse/ah.html
[Tue Jan 19 11:54:23 2016] [error] [client 192.168.0.121] PHP Notice: Undefined index: reqData in /var/www/autHouse/handleRequests.php on line 15, referer: http://192.168.0.12/autHouse/ah.html
你能告诉我为什么我在发送正确的JSON数据时会遵守php吗
问候
J.试试这个
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("POST", "handleRequests.php", true);
xmlhttp.setRequestHeader("Content-Type", "application/json;charset=UTF-8");
xmlhttp.send(jData);
试试这个
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("POST", "handleRequests.php", true);
xmlhttp.setRequestHeader("Content-Type", "application/json;charset=UTF-8");
xmlhttp.send(jData);
您在生成的数组中错过了一个级别
$body = file_get_contents('php://input');
error_log(var_dump($body));
$reqData= json_decode($_POST['reqData'], true);
$reqType = $reqData['reqData']["reqType"];
$reqName = $reqData['reqData']["reqName"];
如果您更喜欢使用传递数据的对象,而不是将对象转换为数组,那么您可以这样做
$body = file_get_contents('php://input');
error_log(var_dump($body));
$reqData= json_decode($_POST['reqData']);
$reqType = $reqData->reqData->reqType;
$reqName = $reqData->reqData->reqName;
您在生成的数组中错过了一个级别
$body = file_get_contents('php://input');
error_log(var_dump($body));
$reqData= json_decode($_POST['reqData'], true);
$reqType = $reqData['reqData']["reqType"];
$reqName = $reqData['reqData']["reqName"];
如果您更喜欢使用传递数据的对象,而不是将对象转换为数组,那么您可以这样做
$body = file_get_contents('php://input');
error_log(var_dump($body));
$reqData= json_decode($_POST['reqData']);
$reqType = $reqData->reqData->reqType;
$reqName = $reqData->reqData->reqName;
试试这个
$reqData=json\u decode($body,true)代码>没有改变任何东西…试试这个$reqData=json\u decode($body,true)代码>没有改变任何事情。。。