Php 如何筛选在每个次要版本中保持最高修补程序版本的阵列?
我有以下数组: array(174) { [0]=> string(5) "3.0.3" [1]=> string(5) "3.0.2" [2]=> string(5) "3.0.1" [3]=> string(5) "3.0.0" [9]=> string(5) "2.9.5" [10]=> string(5) "2.9.4" [11]=> string(5) "2.9.3" [12]=> string(5) "2.9.2" [13]=> string(5) "2.9.1" [14]=> string(5) "2.9.0" [18]=> string(6) "2.8.11" [19]=> string(6) "2.8.10" [20]=> string(5) "2.8.9" }Php 如何筛选在每个次要版本中保持最高修补程序版本的阵列?,php,arrays,semantic-versioning,Php,Arrays,Semantic Versioning,我有以下数组: array(174) { [0]=> string(5) "3.0.3" [1]=> string(5) "3.0.2" [2]=> string(5) "3.0.1" [3]=> string(5) "3.0.0" [9]=> string(5) "2.9.5" [10]=> string(5) "2.9.4" [11]=> string(5) "2.9.3" [12]=> string(5) "2.9.2"
首先,必须按主版本对版本进行分组。之后,您只需使用
version\u compare
函数按降序对结果组进行排序,并返回每个组的第一个元素:
$versions = array("3.0.3", "3.0.2", "3.0.1", "3.0.0", "2.9.5", "2.9.4",
"2.9.3", "2.9.2", "2.9.1", "2.9.0", "2.8.11", "2.8.10", "2.8.9"
);
$groupedVersions = array();
foreach ($versions as $version) {
preg_match('/^\d+\.\d+/', $version, $majorVersion);
if (!isset($groupedVersions[$majorVersion[0]])) {
$groupedVersions[$majorVersion[0]] = array($version);
} else {
$groupedVersions[$majorVersion[0]][] = $version;
}
}
$groupedVersions = array_map(function ($versions) {
usort($versions, 'version_compare');
return array_reverse($versions);
}, $groupedVersions);
$latestVersions = array_reduce($groupedVersions, function ($carry, $versions) {
$carry[] = $versions[0];
return $carry;
}, array());
echo '<pre>';
var_dump($latestVersions);
echo '</pre>';
您只能使用
explode()
并比较每个主变量的最后一个值,然后使用主版本和次版本构建关联数组:
Array
(
[0] => 3.0.3
[1] => 2.9.5
[2] => 2.8.11
)
在PHP中对数组数据进行分组时,通常最有效的方法是根据分组条件生成临时键 我将使用一些基于以下公认答案的版本术语: 在这种情况下,将使用前两个整数(主版本和次版本)(它们必须用分隔符分隔,以避免数据冲突)。迭代时,检查输出集合中是否存在临时键。如果不存在,则添加临时键。如果存在,则检查第三个整数(维护版本)是否大于该主要次要版本组存储的维护版本——如果存在,则替换存储的主要次要版本组的值 这在我下面的代码片段中非常简洁地执行。如果需要对输出进行索引,请调用
array\u values()
,否则省略该步骤
代码:()
输出:
$versions = [
"3.0.1", "3.0.3", "3.0.2", "3.0.0",
"2.9.4", "2.9.3", "2.9.2", "2.9.5", "2.9.1", "2.9.0",
"2.8.1", "2.8.11", "2.8.10"
];
foreach ($versions as $version) {
$ints = explode('.', $version, 3);
$tempKey = "{$ints[0]}.{$ints[1]}";
if (!isset($result[$tempKey]) || version_compare($version, $result[$tempKey], 'gt')) {
$result[$tempKey] = $version;
}
}
var_export(array_values($result));
使用
version\u compare()
是比较版本的合适工具,但是,如果您希望对维护版本值进行简单的整数对整数比较,则可以避免这种情况。这将花费更多的内存,因为您还需要存储一个分组维护版本整数数组来进行比较。我建议只比较完整版本字符串。尽管我真的很喜欢脑筋急转弯。我们希望您已经尝试过了,您尝试过什么吗?此函数可能会有所帮助:是的,我正在尝试解决它。我试图先得到前两个值,然后比较,但我做不到。foreach($key=>$value){$test=substr($value,0,3);$a=strtr($value,array('.=>'','=>'');$b=(int)$a;$c=substr($b,0,2);$new_array=array($c);$result=array_unique($new_array);print_object($result);}使用PHP作为起点;然后,可能需要一个团队来划分主要/次要群体
<?php
$arr = array(0 => "3.0.3", 1 => "3.0.2", 2 => "3.0.1", 3 => "3.0.0", 9 => "2.9.5", 10 => "2.9.4", 11 => "2.9.3", 12 => "2.9.2", 13 => "2.9.1", 14 => "2.9.0", 18 => "2.8.11", 19 => "2.8.10", 20 => "2.8.9");
$versions = array();
$final = array();
foreach ($arr as $version) {
$explode = explode('.', $version); // split all parts
$end = '';
$begin = '';
if (count($explode) > 0) {
$end = array_pop($explode); // removes the last element, and returns it
if (count($explode) > 0) {
$begin = implode('.', $explode); // glue the remaining pieces back together
}
}
if(!empty($versions[$begin])){
if($versions[$begin] < $end){
$versions[$begin] = $end;
}
}else{
$versions[$begin] = $end;
}
}
foreach($versions as $key=>$value){
$final[] = "$key.$value";
}
print_r($final);
?>
Array
(
[0] => 3.0.3
[1] => 2.9.5
[2] => 2.8.11
)
$versions = [
"3.0.1", "3.0.3", "3.0.2", "3.0.0",
"2.9.4", "2.9.3", "2.9.2", "2.9.5", "2.9.1", "2.9.0",
"2.8.1", "2.8.11", "2.8.10"
];
foreach ($versions as $version) {
$ints = explode('.', $version, 3);
$tempKey = "{$ints[0]}.{$ints[1]}";
if (!isset($result[$tempKey]) || version_compare($version, $result[$tempKey], 'gt')) {
$result[$tempKey] = $version;
}
}
var_export(array_values($result));
array (
0 => '3.0.3',
1 => '2.9.5',
2 => '2.8.11',
)