Php 此代码不断返回错误：未知列'；房子教堂的名称'；在'；字段列表'；

我的问题是：

CREATE TABLE IF NOT EXISTS `church_report` (
  `report_id` int(11) NOT NULL AUTO_INCREMENT,
  `NAME_OF_DEPUTY_SHERHERD` varchar(255) NOT NULL,
  ` NAME_OF_HOUSE_CHURCH` varchar(255) NOT NULL,
  `Date` date NOT NULL,
  `ADDRESS` varchar(255) NOT NULL,
  `MEMBERS_PRESENT` varchar(255) NOT NULL,
  `ADULTS_1` int(11) NOT NULL,
  `ADULTS_2` int(11) NOT NULL,
  `ADULTS_3` int(11) NOT NULL,
  `ADULTS_4` int(11) NOT NULL,
  `ADULTS_5` int(11) NOT NULL,
  `ADULTS_6` int(11) NOT NULL,
  `ADULTS_7` int(11) NOT NULL,
  `ADULTS_8` int(11) NOT NULL,
  `ADULTS_9` int(11) NOT NULL,
  `ADULTS_10` int(11) NOT NULL,
  `ADULTS_11` int(11) NOT NULL,
  `ADULTS_12` int(11) NOT NULL,
  `ADULTS_13` int(11) NOT NULL,
  `ADULTS_14` int(11) NOT NULL,
  `ADULTS_15` int(11) NOT NULL,
  `ADULTS_16` int(11) NOT NULL,
  `CHILDREN_ATTENDED` varchar(255) NOT NULL,
  `CHILDREN1` int(11) NOT NULL,
  `CHILDREN2` int(11) NOT NULL,
  `CHILDREN_3` int(11) NOT NULL,
  `CHILDREN_4` int(11) NOT NULL,
  `CHILDREN_5` int(11) NOT NULL,
  `CHILDREN_6` int(11) NOT NULL,
  `CHILDREN_7` int(11) NOT NULL,
  `CHILDREN_8` int(11) NOT NULL,
  `CHILDREN_9` int(11) NOT NULL,
  `CHILDREN_10` int(11) NOT NULL,
  `CHILDREN_11` int(11) NOT NULL,
  `CHILDREN_12` int(11) NOT NULL,
  `CHILDREN_13` int(11) NOT NULL,
  `CHILDREN_14` int(11) NOT NULL,
  `ABSENTEES_AND_REASON` varchar(255) NOT NULL,
  `DID_EVERY_MEMBER_DO_THEIR_DUTIES` tinyint(1) NOT NULL,
  `If_No` varchar(255) NOT NULL,
  `WAS_THE_PROGRAMME_FOLLOWED` tinyint(1) NOT NULL,
  `If_No_Why` varchar(255) NOT NULL,
  `WHAT_ITEM_OF_THE_PROGRAMME` varchar(255) NOT NULL,
  `WHAT_ITEM_OF_THE_PROGRAMME_WAS_NOT` int(11) NOT NULL,
  `RATE1` varchar(255) NOT NULL,
  `RATE2` int(11) NOT NULL,
  `RATE3` int(11) NOT NULL,
  `RATE4` int(11) NOT NULL,
  `RATE5` int(11) NOT NULL,
  `IF_YOU_RATED_IN_FROM_1_3` varchar(255) NOT NULL,
  `V_I_P` tinyint(1) NOT NULL,
  `A_PROFILE_OF_THE_V_I_P` varchar(255) NOT NULL,
  `DID_YOU_CAST_THE_VISION` tinyint(1) NOT NULL,
  `IF_NO_WHY_NOT` varchar(255) NOT NULL,
  `IF_YES_HOW_DID_YOU_DO_IT` varchar(255) NOT NULL,
  `PASTORVILLAGE` varchar(255) NOT NULL,
  `OTHER_COMMENTS` varchar(255) NOT NULL,
  PRIMARY KEY (`report_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

$sql = "INSERT INTO church_report 
        (NAME_OF_DEPUTY_SHERHERD, NAME_OF_HOUSE_CHURCH, Date, ADDRESS, 
        ADULTS_1, ADULTS_2, ADULTS_3, ADULTS_4, ADULTS_5, ADULTS_6, 
        ADULTS_7, ADULTS_8, ADULTS_9, ADULTS_10, ADULTS_11, ADULTS_12, 
        ADULTS_13, ADULTS_14, ADULTS_15, ADULTS_16, CHILDREN1, CHILDREN2, 
        CHILDREN_3, CHILDREN_4, CHILDREN_5, CHILDREN_6, CHILDREN_7, 
        CHILDREN_8,CHILDREN_9, CHILDREN_10, CHILDREN_11, CHILDREN_12, 
        CHILDREN_13, CHILDREN_14, ABSENTEES_AND_REASON, DID_EVERY_MEMBER_DO_THEIR_DUTIES, 
        If_No, WAS_THE_PROGRAMME_FOLLOWED, If_No_Why, WHAT_ITEM_OF_THE_PROGRAMME, 
        WHAT_ITEM_OF_THE_PROGRAMME_WAS_NOT, RATE1, RATE2, RATE3, RATE4, RATE5, 
        IF_YOU_RATED_IN_FROM_1_3, V_I_P, A_PROFILE_OF_THE_V_I_P, DID_YOU_CAST_THE_VISION, 
        IF_NO_WHY_NOT, IF_YES_HOW_DID_YOU_DO_IT, PASTOR_VILLAGE, OTHER_COMMENTS)  

        VALUES ('value', 'value1', 'value2', 'value3', 'value5', 'value6', 'value7',
        'value8', 'value9', 'value10','value11', 'value12', 'value13', 'value14', 
        'value15', 'value16', 'value17', 'value18', 'value19', 'value20','value22', 
        'value23', 'value24', 'value25', 'value26', 'value27', 'value28', 'value29', 
        'value30', 'value31', 'value32', 'value33', 'value34', 'value35', 'value36', 
        'value37', 'value38', 'value39', 'value40', 'value41', 'value42', 'value43', 
        'value44', 'value45', 'value46', 'value47', 'value48', 'value49', 'value50', 
        'value51', 'value52', 'value53', 'value54', 'value55')";  
        // $success = mysql_query($sql); 

---

SQL错误是有效的，因为您的表架构中有一个空格，因此呈现的查询不正确：

`NAME_OF_DEPUTY_SHERHERD` varchar(255) NOT NULL,
` NAME_OF_HOUSE_CHURCH` varchar(255) NOT NULL, <-- Here is the space!
`Date` date NOT NULL,

---

另外，建议您将

mysql（）

函数更新为至少

mysqli（）

或

pdo

函数。

确保church_报告表中存在此列。如错误所述，您的表格中没有“教堂名称”列。您好，请参见图片您在“教堂名称”中有空格，因此错误是正确的。改为

'NAME\u OF theu HOUSE\u CHURCH`

这应该是一个拼写错误，因为这就是它最后的全部内容。

`NAME_OF_DEPUTY_SHERHERD` varchar(255) NOT NULL,
`NAME_OF_HOUSE_CHURCH` varchar(255) NOT NULL, <-- Space removed!
`Date` date NOT NULL, 

$sql = "INSERT INTO church_report 
        (`NAME_OF_DEPUTY_SHERHERD`, ` NAME_OF_HOUSE_CHURCH`, ....