php pdo从包含多个where子句的多个表中进行选择

我不熟悉PHP PDO，并将一些常规MySQL查询转换为PDO

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

当指定的值替换SQL语句中的当前占位符时，在phpMyAdmin中测试时，下面的查询非常有效。但是，当我将其配置为像现在使用PDO一样工作时，它不会产生任何结果或错误。有人能告诉我或告诉我我做错了什么吗

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

有人告诉我不能在数组中传递参数作为引用

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

如果正确，那么创建解决方案的最佳方法是什么？只使用传递给变量$uid的用户ID。谢谢

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

//创建qd_user_usam表的sql

WHERE u.user_id = :uID AND a.acl_id = :aID AND g.group_id = :gID AND e.entry_id = :eID AND p.permit_id = :pID";

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

---

你把事先准备好的陈述搞错了。

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

Thy不能用于表示查询中的任何值，而只能动态添加数据

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

而a.group_id是一个列名，必须按原样编写，不需要准备语句

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

---

问题是，您正试图通过将连接的列绑定为参数来隐式编写连接，这是行不通的。参数不能引用其他列；在本例中，它们被视为字符串。如果像这样重写查询，则应修复连接问题：

<p>try
{</p>
   <p>// Build the database PDOStatement</p>
   <pre>$_stmt = $this->_dbConn->prepare($sql);</pre>
   <pre>$_stmt->execute($array);</pre>
<pre>}
catch(PDOException $e)
{</pre>
    <pre>$this->_errorMessage .= 'Error processing user login access. <br /> Line #'.__LINE__ .' '.$e ;</pre>  
    <pre>die($this->_errorMessage);
}</pre>

<pre>$results = $_stmt->fetchAll(PDO::FETCH_ASSOC);</pre>
<pre>return $results;</pre>

<pre>$results = null;</pre>
<pre>$this->_dbConn = null;</pre>

---

它现在运行得很好，感谢您的明确细节和解释；我可以清楚地看到我做错了什么。这种方法也很有效，而且它已经到了我看得太多的地步。谢谢