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Php 使用@if时尝试获取非对象的属性_Php_Laravel_Laravel Blade - Fatal编程技术网

Php 使用@if时尝试获取非对象的属性

Php 使用@if时尝试获取非对象的属性,php,laravel,laravel-blade,Php,Laravel,Laravel Blade,错误: 我的代码: 索引-debito.blade Trying to get property 'desp_indevida' of non-object (View: D: \...\detalhamento\index-debito.blade.php) 此错误仅发生在某些寄存器上您可以使用isset@if(isset($value->despesa->desp_indevida)和&$value->despesa->desp_indevida==1)检查$value->despesa对

错误:

我的代码:

索引-debito.blade

Trying to get property 'desp_indevida' of non-object (View: D: \...\detalhamento\index-debito.blade.php)

此错误仅发生在某些寄存器上

您可以使用isset@if(isset($value->despesa->desp_indevida)和&$value->despesa->desp_indevida==1)检查
$value->despesa
对于一个或多个
$detalhamento
迭代很可能
为null
,因此您无法访问
desp_indevida
。尝试使用
@if($value->despesa&&value->despesa->desp_indevida==1)
,或者如果您有PHP8,
@if($value->despesa&->desp_indevida==1)
@foreach ($detalhamento as $value)
     <tr>
     @if(!is_null($value->despesa_id))
        @if($value->despesa->desp_indevida == 1)
            <td>Indevido</td>
        @elseif(isset($value->pago_aplicacao))
            <td>Pago Aplicação</td>
        @elseif(isset($value->indevidos_id))
            <td>Indevido</td>
        @else
            <td>Programada</td>
    @endif
@endforeach
public function despesa()
{
    return $this->belongsTo(Despesa::class,'despesa_id','id');
}